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Degger [83]
3 years ago
5

Students investigating chemical reactions conducted the experiment you see here. An antacid tablet was dropped into a plastic ba

g containing 10 ml distilled water at 22oC. The bag was immediately zipped closed and the chemical reaction proceeded until completion. Based on your knowledge of chemical reactions, choose all of the statements below would apply?
A) the tablet completely disappeared.
B) The total mass at the completion of the experiment is 16.72g.
C) The mass of the products is slightly less than the mass of the reactants.
D) A decrease in the mass of the products in the result of the production of a gas.
E) Evidence of a chemical reaction includes the production of something new: a gas
Chemistry
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer: B and E

Explanation:

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Balance the following:<br> _H2SO4 + _NaNO2 → _HNO2 + _Na2SO4
Alisiya [41]

Answer:

it is balanced

Explanation:

i solved it

4 0
3 years ago
Read 2 more answers
Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 100 / 17

Mole of NH₃ = 5.88 moles

Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

Pressure (P) = 95 KPa

Temperature (T) = 15 °C = 15 + 273 = 288 K

Number of mole of H₂ (n) = 8.82 moles

Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

PV = nRT

95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

8 0
3 years ago
Define shielding and effective nuclear charge. What is the connection between the two?
ivolga24 [154]

Answer:

The relation between the shielding and effective nuclear charge is given as

Z_{eff} = Z -S

where s denote shielding

z_{eff} denote effective nuclear charge

Z - atomic number

Explanation:

shielding is referred to as the repulsion of an outermost electron to the pull of electron from valence shell.  Higher the electron in valence shell higher will be the shielding effects.  

Effective nuclear charge is the amount of net positive charge that valence electron has.

The relation between the shielding and the effective nuclear charge is given as  

Z_{eff} = Z -S

wheres denote shielding

z_{eff} denote effective nuclear charge  

Z - atomic number

8 0
3 years ago
1. How many molecules of S2 gas are in 756.2 L?
AfilCa [17]

Answer: There are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

Explanation:

It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol

According to mole concept, 1 mole of every substance contains 6.022 \times 10^{23} molecules.

Therefore, molecules of S present in 33.76 moles are calculated as follows.

1 mol = 6.022 \times 10^{23}\\33.76 mol = 33.76 \times 6.022 \times 10^{23}\\= 2.032 \times 10^{25}

Thus, we can conclude that there are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

5 0
3 years ago
2. Aqueous lead (II) nitrate reacts with aqueous potassium chloride and produces
Rom4ik [11]

Answer:

302i83oeheiehdodnfifnf

Explanation:

7 0
3 years ago
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