Answer:
The total pressure is 0.8 atm
Explanation:
<u>Step 1</u>: The balanced equation
2 A(g) + 3 B(g) → A2B3 (g)
This means that for 2 moles of A consumed, we need 3 moles of B to produce 1 mole of A2B3
Initial pressure of A = 1.20 atm
Initial pressure of B = 1.20 atm
<u>Step 2</u>: Calculate limiting reactant and reactant in excesss
If 3 moles of B need 2 moles of A to be consumed; then 1.2 mole of B needs 0.8 moles of A.
0.8 moles of A will be consumed, this means 0.4 moles will remain.
⇒ A is in excess
B will completely react, so B is the limiting reactant
If 3 moles of B need 2 moles of A to be consumed; then 0.4 moles of A2B3 will be produced.
<u>Step 3</u>: Calculate the total pressure
Final pressure of A = 0 atm
Final pressure of B = (1.20 - 0.80) atm = 0.40 atm
Final pressure of A₂B₃ = 0.40 atm
Total pressure = pressure A + pressure B + pressure A2B3 = 0 atm + 0.4 atm + 0.4 atm = 0.8 atm