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PilotLPTM [1.2K]
3 years ago
9

Which option draws the correct conclusion from the following case study?

Chemistry
2 answers:
trasher [3.6K]3 years ago
4 0

Answer:

I believe the answer The case study was influenced by bias, and led to incorrect conclusions being drawn. plz correct me if I am wrong

Explanation:

TiliK225 [7]3 years ago
4 0

Answer: options B

Explanation:

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3. 78 mL of 2.5 M phosphoric acid is neutralized with 500 mL of potassium hydroxide. What is the
xenn [34]

Hence, concentration of base is 1.17 M
7 0
3 years ago
Estimate the ph of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate (na2hpo4) and 1.25 mole of hyd
GenaCL600 [577]

The HCl added = 1.25 moles

and the moles of Na2HPO4 = 1 mole

Now when acid is added in the given solution of Na2HPO4

One mole of H+ will react with one mole of Na2HPO4 to given one mole of NaH2PO4

Na2HPO4  + H+  ---> NaH2PO4

Now this one mole formed NaH2PO4 will further react with 0.25 moles of H+ left to form 0.25 moles of  H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution

So this will result into formation of a buffer of phosphoric acid and NaH2PO4

NaH2PO4  + H+  ---> H3PO4

pKa of H3PO4 = 2.1

so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58

so the pH will be in between 2.1 to 7.2

7 0
3 years ago
What 3 classes of compounds are elecrolytes
zvonat [6]

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

4 0
3 years ago
A molcule is the smallest part of
telo118 [61]

Answer:

compound

Explanation:

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.

8 0
3 years ago
Denver, Colorado (altitude above sea level is 5,280 ft) has an atmospheric pressure of 633. mm Hg. Calculate the boiling point o
Fed [463]

Answer:

T2 = 94.6 C

Explanation:

Use Clausius-Clayperyon equation.

ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K

P1 = 760 mmHg

P2 = 630 mmHg  

T1 = 373 K

T2 = ?

∆Hvap = 40.7 kJ/mole

R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)

Plug in and solve for T2

ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)

T2 = 367.74 K = 94.6 C

8 0
3 years ago
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