3 years ago

Find the area of a kites with diagonals 6.5in and 10in. I need work shown plz help!!!!!

1 answer:

8 0

The area of a kite is:

A=(d1*d2)/2, where d1 and d2 are the two diagonals

In this case:

A=6.5*10/2

A=32.5 in^2

You might be interested in

Fudgin [204]

Answer: 4th graph

Step-by-step explanation:

7 0

3 years ago

valentina_108 [34]

Answer:

Reflect Quadrilateral A over the x-axis. Label the image quadrilateral B. Reflect

Quadrilateral B over the y-axis. Label the image C.

Step-by-step explanation:

3 0

2 years ago

Kaylis [27]

113 I’m pretty sure or 78 so H or G

4 0

3 years ago

Lena [83]

Answer:

3.72

Step-by-step explanation:

5 0

3 years ago

fgiga [73]

Angle1 = 90 degrees

Angle2 = 15 degrees

Angle3 = 75 degrees (because 180-15-90=75 and all angles equal 180 degrees)

Side1 = 300

Side2 = x (unknown)

Solve for x:

X / sin(15degrees) = 300 / sin(75degrees)

X = (300•sin(15degrees)) / sin(75degrees)

X = 80.38...

= 80

8 0

3 years ago