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Dvinal [7]
3 years ago
5

What is the correct answer?

Physics
2 answers:
Lemur [1.5K]3 years ago
6 0
The remainder is 39.

bija089 [108]3 years ago
4 0

Answer:

(B) 39

Explanation:

Use synthetic division:

-2 | 3  0  -1    3  1

____<u>-6 12 -22 38</u>

     3 -6 11  -19 | 39

This means that the remainder is 39

You might be interested in
It takes Serina 0.25 hours to drive to school. Her route is 16 km long. What is Serina’s average speed on her drive to school?
tankabanditka [31]

Answer:

17.78 m/s

Explanation:

Average speed is found by simply dividing the distance travelled by the time that it took to finish the trip. It's measured in meters per second (m/s), so first convert the quantities.

1 km = 1000 m, so 16 km is 16000 m

0.25 hours is 15 minutes. Since 1 minute is 60 seconds, then 15 minutes must be 900 seconds.

Thus:

average speed = total distance/total time = 16000 m / 900 s = 17.78 m/s

Hope this helps!

Brainliest please!

5 0
3 years ago
A 19-year old soccer player extends their right knee from an initial angle of 20o to 140o in 2 s. If this movement began from re
Mandarinka [93]

Answer: 32π/9 rad/s²

Explanation: initial angular displacement = 20°, final angular displacement = 140°, average time = 2s.

We need to convert the angular displacements to radian.

Recall that 2π = 360°, hence 20° = (20 × 2π)/360 = π/9 rad

Converting 140° to radian we have that

140° = (140 × 2π)/360 = 7π/9

Initial angular displacement = π/9 rad

Final angular displacement = 7π/9

Average angular velocity = change in angular displacement /time

Average angular velocity = 7π /9 - π/9/2

Average angular velocity = (8π/9)/2

Average angular velocity = 16π/9 rad/s

Average angular acceleration = average angular velocity / time taken

Average angular acceleration = (16π/9)/2

Average angular acceleration = 32π/9 rad/s²

4 0
4 years ago
When dogs see police dogs do they think "oh no its the cops"?
ira [324]

No they say "Watch out it's the fuzz"

4 0
3 years ago
Read 2 more answers
A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a
IgorLugansk [536]

Answer:1.5

Explanation:

Given

mass of first  cart m_1=6 kg

initial Velocity u_1=3 m/s

mass of second cart m_2=3 kg

u_2=0 m/s

In the absence of External Force we can conserve momentum

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{m_1+m_2}

v=\frac{6\times 3+3\times 0}{6+3}

v=2 m/s

Final kinetic Energy of two masses

K.E._2=\frac{1}{2}(m_1+m_2)v^2

K.E._2=\frac{1}{2}\cdot (3+6)\cdot (2)^2

K.E._2=18 J

Initial Kinetic Energy

K.E._1=\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2

K.E._1=\frac{1}{2}6\times 3^2+0

K.E._1=27 J

ratio =\frac{K.E._1}{K.E._2}=\frac{27}{18}=1.5

5 0
4 years ago
If a bowling ball rolls 12 meters in 2.2 seconds what is the speed ?
Evgesh-ka [11]

Answer:19000

Explanation:I don’t know

8 0
4 years ago
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