You can hear a difference between these two sounds. That is because their pitch isdifferent. Pitch depends on the frequency of a sound wave. ... High sounds have highfrequencies and low sounds have lowfrequencies.
I think it false. Sorry if i'm wrong.
Answer:C
Explanation:BECASE THEY ARE ONE OF THE PEST KILLERS SRY BUT IM THE MYSTER MAN WHOOOSH ????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? OH AND PLS FOR BRAINIEST
use F = ma
F : force m : mass a : acceleration
so
f = 5kg * 20 m/s2 = 100 N
Answer:
740 N
Explanation:
We are given that
Radius,r=0.3 m
Torque,
We have to find the magnitude of the static frictional force.
According to question
Torque by engine=Torque by static friction




Hence, the magnitude of static frictional force=740 N