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Alchen [17]
3 years ago
15

Is this an example of an elastic collision or inelastic collision? A 200-kg bumper car stopped at an intersection is rear-ended

by an 1100-kg truck
Inoving at 13 m/s. If the car was in neutral and the brakes were off, the bumper car would BOUNCE OFF of the truck into the intersection.​
Physics
1 answer:
Alina [70]3 years ago
4 0

Answer:

inelastic collision.

Explanation:

An elastic collision consists in a collision in wich the bodies implied bounce off. Furthermore, the momentum of the bodies is conserved.

In as inelastic collision the momentum is not conserved, and is possible that the bodies implied in the collision stay joint after the collision.

In this case yo have that both bumper car and truck stayed joint after the collision. Hence, this situation is an inelastic collision.

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What are the horizontal and vertical components of a lizard’s displacement if it has climbed 7m directly up a tree?
madam [21]

Answer:

The horizontal component is zero.

The vertical component is 7\sin\theta

Explanation:

Given that,

The lizard climb 7m directly up on a tree.

We know that,

The horizontal component is

x=\cos\theta

The vertical component is

y=\sin\theta

If the lizard climb 7m directly up on a tree then,

We need to find the components

Using given data

The horizontal component of lizard is

x=0

The vertical component is

y=7\sin\theta

Hence, The horizontal component is zero.

The vertical component is 7\sin\theta

7 0
3 years ago
IMPORTANT 3 QUESTIONS!
Brums [2.3K]

Answer:

7. 20,000,000 mL.

8. 8,000 m.

9. 120,000 secs.

10. 4

Explanation:

7. Determination of the volume in millilitres (mL)

Volume in litre (L) = 20,000 L

Volume in millilitres (mL) =..?

The volume in mL can be obtained as follow:

1 L = 1,000 mL

Therefore,

20,000 L = 20,000 x 1,000 = 20,000,000 mL.

Therefore, 20,000 L is equivalent to 20,000,000 mL.

8. Determination of the distance in metre (m)

Distance in mile = 5 mile

Distance in metre =?

First, we shall convert from mile to kilometre.

This can be done as follow:

1 mile = 1.6 km

Therefore,

5 mile = 5 x 1.6 = 8 km

Finally, we shall convert 8 km to metre (m).

This is illustrated below:

1 km = 1,000 m

Therefore,

8 km = 8 x 1,000 = 8,000 m

Therefore, 5 miles is equivalent to 8,000 m.

9. Determination of the time in seconds.

Time = 400 minutes for 5 days.

First, we shall convert 400 mins to hour.

This is illustrated below:

60 minutes = 1 hour

Therefore,

400 mins = 400/60 = 20/3 hours

The time (hours) is 20/3 hours in 1 day.

Therefore, the time (hours) in 5 days will be = 20/3 x 5 = 100/3 hours.

Next, we shall convert 100/3 hours to minutes.

This is illustrated below:

1 hour = 60 minutes

Therefore,

100/3 hours = 100/3 x 60 = 2000 mins

Finally, we shall convert 2000 mins to seconds.

This is illustrated below:

1 mins = 60 secs

2000 mins = 2000 x 60 = 120,000 secs.

Therefore, the time is 120,000 secs.

10. Determination of the number of significant figures.

To obtain the significant figures of a number, we simply count all the numbers available.

Therefore, the number of significant figures for 9876 is 4.

6 0
3 years ago
A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?
Agata [3.3K]

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book  = 1.15kg

Unknown:

Magnitude of the normal force  = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

 Normal force  = mass x acceleration due to gravity

 Normal force  = 1.15 x 9.8  = 11.27N

5 0
3 years ago
A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential
castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot d

\Delta U=-q(E\cdot d)

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

\Delta U=3.32\times10^{-3}\ J

The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

3 0
3 years ago
A car moving at 30 m/s slows uniformly to a speed of 10 m/s in a time of 5 s. Determine 1. The acceleration of the car. 2. The d
ValentinkaMS [17]

Answer:

Explanation:

Initial velocity , u = 30 m/s

final velocity , v = 10 m/s

time , t = 5 seconds

1. Acceleration = v - u / t

= 10 - 30 / 5

= -20 / 5

= <u><em>- 4 m/s</em></u>

8 0
3 years ago
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