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NikAS [45]
3 years ago
6

Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo

n moved at a velocity of 3.5 m/s east, while the other moved at a velocity of 2.75 m/s west. After the collision, one balloon moves at a velocity of 1.5 m/s west. What is the velocity of the other water balloon?
Physics
1 answer:
bagirrra123 [75]3 years ago
5 0
By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>
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Question is down below
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The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

<h3>What are the components of velocity?</h3>

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

Hence;

Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

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Water flows without friction vertically downward through a pipe and enters a section where the cross sectional area is larger. T
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As according to the problem, A_{2} > A_{1}, so from the above formula v_{2} < v_{1}.

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