Answer:
A. 46.15 ohms
B. 1248 W
C. 2.25×10⁶ J
Explanation:
A. Determination of the resistance.
Current (I) = 5.2 A
Voltage (V) = 240 V
Resistance (R) =?
From ohm's law,
V = IR
240 = 5.2 × R
Divide both side by 5.2
R = 240 / 5.2
R = 46.15 ohms
B. Determination of the power.
Current (I) = 5.2 A
Voltage (V) = 240 V
Power (P) =?
P = IV
P = 240 × 5.2
P = 1248 W
C. Determination of the energy.
Power (P) = 1248 W
Time (t) = 30 minutes
Energy (E) =?
Next, we shall convert 30 minutes to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
30 min = 30 min × 60 s / 1 min
30 min = 1800 s
Finally, we shall determine the energy. This can be obtained as illustrated below:
Power (P) = 1248 W
Time (t) = 1800 s
Energy (E) =?
E = Pt
E = 1248 × 1800
E = 2.25×10⁶ J
Many ways for example they look up related things and study them or they can test it and see what happens
When two sprockets are in contact with each other then at the contact of sprockets the tangential velocity and tangential acceleration of the sprockets must be same.
Now we can say that tangential velocity is given as
v = Rw
here we know that
![w = 2\pi f](https://tex.z-dn.net/?f=w%20%3D%202%5Cpi%20f)
also we can say
![2\pi R = N*x](https://tex.z-dn.net/?f=2%5Cpi%20R%20%3D%20N%2Ax)
x = width of each sprocket
So tangential speed is given as
![v = \frac{N*x}{2\pi} * 2\pi f](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7BN%2Ax%7D%7B2%5Cpi%7D%20%2A%202%5Cpi%20f)
now since tangential speed of two sprockets are same
![N_1*x*f_1 = N_2*x*f_2](https://tex.z-dn.net/?f=%20N_1%2Ax%2Af_1%20%3D%20N_2%2Ax%2Af_2)
given that
= 50
= 20 rpm
= 30
now from above equation
![50*20 = f_2 * 30](https://tex.z-dn.net/?f=50%2A20%20%3D%20f_2%20%2A%2030)
rpm
I mean if he flies 5g that means that's his average speed too