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sweet [91]
3 years ago
8

An experiment is conducted in which red light is diffracted through a single slit. part a listed below are alterations made, one

at a time, to the original experiment, and the experiment is repeated. after each alteration, the experiment is returned to its original configuration. which of these alterations decreases the angles at which the diffraction minima appear? select all that apply. view available hint(s) select all that apply. a green, rather than red, light source is used. the slit width is halved. the slit width is doubled. the distance between the slits and the screen is doubled. the distance between the slits and the screen is halved. the experiment is conducted in a water-filled tank.
Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Color spectrum

<h2>Further Explanation </h2>

A spectrum is a condition or price that is not limited to a set price but can change indefinitely on a continuum. This word evolved from the Latin word, specter, which means ghosts, but the modern meaning now comes from its use in natural science. A spectrum is a condition or price that is not limited to a set price but can change indefinitely on a continuum. This word evolved from the Latin word, specter, which means ghosts, but the modern meaning now comes from its use in natural science. White is an impression that is captured by the eye and is a combination (superposition of several wavelengths) of various unique wavelengths.

For an easy example, I take the example of white can be produced from a combination of 3 wavelengths of Red Green and Blue or RGB (Red Green Blue).

Spectral is the result of the interaction between electromagnetic energy (EM) and an object. There are objects that have absorption properties (absorption) of high EM and low reflections, otherwise, there are objects that have low absorption and high reflectivity. These reflection and absorption patterns are different for different wavelengths. If it is associated with satellite images, then each object will provide a different EM reflection, so that we are able to distinguish an object from another object (identification). The instrument used to measure the reflectance value of an object is called a spectrometer. On the market there are spectrometers of higher spectral resolution, in addition, there are also spectrometers that can be used underwater (underwater).

the red color is produced from electromagnetic wavelengths/light in the range of 700-630 nanometers.

the green color is produced from electromagnetic/light wavelengths in the range of 560-490 nanometer meters.

the blue color is produced from electromagnetic/light wavelengths in the range of ~ 490-450 nanometer meters.

Learn more

Color spectrum brainly.com/question/12464893

Details

Grade:  High School

Subject:  Physics

keywords: Color spectrum

LenaWriter [7]3 years ago
6 0

Answer:

Where is the rest of the article to read form at?

Explanation:

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___________is the tendency of an object to resist change in its state of motion
Mademuasel [1]
Inertia
<span> An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.this tendency to retain its motion is referred to as Inertia </span>
5 0
3 years ago
A rock that has deformed ____ under stress keeps its new shape when the stress is released.
Anna007 [38]

Answer:

Elastically

Explanation:

A rock that has deformed Elastically under stress keeps its new shape when the stress is released.

In elastic deformation the original shape of the object is regained when the stress is removed. Whereas in plastic deformation the original shape is parmanently deformed with the application of stress.

8 0
3 years ago
A jogger runs by a river with a velocity of 7 m s relative to the ground. A leaf floating on the river moves with a velocity of
Hunter-Best [27]

Answer:

The velocity of the leaf relative to the jogger is 5 m/s.                    

Explanation:

Given that,

Velocity of jogger wrt to the ground, V_j=7\ m/s

velocity of leaf wrt the ground, v_i=2\ m/s

We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.

3 0
4 years ago
Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
Gwar [14]

Explanation:

It is given that,

    \frac{dx}{dt} = -40 mi/h,     \frac{dx}{dt} = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find \frac{dz}{dt}. Equation for the given variables according to the Pythagoras theorem is as follows.

              z^{2} = x^{2} + y^{2}

Now, we will differentiate each side w.r.t 't' as follows.

        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

or,          \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

                       = \frac{-140 - 120}{5}

                       = 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0
3 years ago
At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107
dangina [55]

Answer:

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

Explanation:

The bulk modulus is represented by the following differential equation:

K = - V\cdot \frac{dP}{dV}

Where:

K - Bulk module, measured in pascals.

V - Sample volume, measured in cubic meters.

P - Local pressure, measured in pascals.

Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

-\frac{K \,dV}{V} = dP

This resultant expression is solved by definite integration and algebraic handling:

-K\int\limits^{V_{f}}_{V_{o}} {\frac{dV}{V} } = \int\limits^{P_{f}}_{P_{o}}\, dP

-K\cdot \ln \left |\frac{V_{f}}{V_{o}} \right| = P_{f} - P_{o}

\ln \left| \frac{V_{f}}{V_{o}} \right| = \frac{P_{o}-P_{f}}{K}

\frac{V_{f}}{V_{o}} = e^{\frac{P_{o}-P_{f}}{K} }

The final volume is predicted by:

V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }

If V_{o} = 1\,m^{3}, P_{o} - P_{f} = -10132500\,Pa and K = 2.3\times 10^{9}\,Pa, then:

V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }

V_{f} \approx 0.996\,m^{3}

Change in volume due to increasure on pressure is:

\Delta V = V_{o} - V_{f}

\Delta V = 1\,m^{3} - 0.996\,m^{3}

\Delta V = 0.004\,m^{3}

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

8 0
3 years ago
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