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Answer:
680g of mercury is the mass of the sample of mercury.
Explanation:
Density is an unit used to relates the mass of an object per unit of volume.
For example, in the problem, the density of mercury is 13.6g/cm³, as cm³ is equal to milliliters, mL, the density is: 13.6g/mL.
If you have 50.0mL of mercury, the mass is:
50.0mL * (13.6g / mL) =
<h3>680g of mercury is the mass of the sample of mercury.</h3>
Explanation:
It is known that for first order reaction, the equation is as follows.
t = ![\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}](https://tex.z-dn.net/?f=%5Cfrac%7B2.303%7D%7BK%7D%20log%20%5Cfrac%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bo%7D%7D%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D%7D)
t = ?, K = rate constant = 79 1/s
Initial conc. of
= 1.68
Decompose amount of
= 52% of 1.68
= 
= 0.8736
= 0.87
Now,
= (1.68 - 0.87)
= 0.81
Therefore, calculate the value of t as follows.
t = ![\frac{2.303}{K} log \frac{[C_{4}H_{8}]_{o}}{[C_{4}H_{8}]_{t}}](https://tex.z-dn.net/?f=%5Cfrac%7B2.303%7D%7BK%7D%20log%20%5Cfrac%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bo%7D%7D%7B%5BC_%7B4%7DH_%7B8%7D%5D_%7Bt%7D%7D)
= 
= 
=
s
= 
Thus, we can conclude that 0.00921 s will be taken for 52% of the cyclobutane to decompose.
More details? Can’t do anything wit that
Answer:
They have the same number of atoms
Explanation:
The mole (symbol: mol) is the base unit of amount of substance.
Think of mole meaning like inch. An inch of grass is the same as an inch of a flower. Mole is the standard measuring unit of atoms.