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g100num [7]
3 years ago
5

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

the base titrant volume as 2.04 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 20.95 mL. What volume, in mL, of base was required for the titration?
Chemistry
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

18.91 ml

Explanation:

Initial volume of base=2.04 ml

Final volume of base = 20.95 ml

Volume of base used= 20.95 - 2.04 = 18.91 ml

Note that the volume of base used is obtained as the difference between the final and initial volume of base, hence the answer given above.

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SVETLANKA909090 [29]

Answer:

Explanation:

1. Please provide the enthalpy info - I will work on it with the info

2.

i) Reaction a should be modified to match the number of S in equation:

 2S + 2O2 -> 2SO2     deltaH = -370kJ

ii) Reaction b should be written reversely to match the reactants of SO2:

 2SO2 + O2 -> 2SO3     deltaH = 256kJ

iii) Adding the equations together:

 2S + 3O2 -> 2SO3

iv) Enthalpy of the combined reaction = -370+256 = -114kJ

 It is negative so the reaction is exothermic.

5 0
3 years ago
Read 2 more answers
A or B i need help fast
Bezzdna [24]

Answer: I would go with B

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5 0
3 years ago
How many moles of H2SO4 are needed to prepare 200 mL of a 1.0 M solution?
jok3333 [9.3K]
The answer is 0.2moles
4 0
3 years ago
24. H2SO4 has
Eddi Din [679]

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3 0
3 years ago
658 mL of 0.250 M HCl solution is mixed with 325 mL of 0.600 M HCl solution. What is the molarity of the resulting solution
Tju [1.3M]

The molarity of the resulting solution obtained by mixing 658 mL of 0.250 M HCl solution with 325 mL of 0.600 M HCl solution is 0.366 M

We'll begin by calculating the number of mole of HCl in each solution. This can be obtained as follow:

<h3>For solution 1:</h3>

Volume = 658 mL = 658 / 1000 = 0.658 L

Molarity = 0.250 M

<h3>Mole of HCl =?</h3>

Mole = Molarity x Volume

Mole of HCl = 0.250 × 0.658

<h3>Mole of HCl = 0.1645 mole</h3>

<h3>For solution 2:</h3>

Volume = 325 mL = 325 / 1000 = 0.325 L

Molarity = 0.6 M

<h3>Mole of HCl =?</h3>

Mole = Molarity x Volume

Mole of HCl = 0.6 × 0.325

<h3>Mole of HCl = 0.195 mole</h3>

  • Next, we shall determine the total mole of HCl in the final solution. This can be obtained as follow:

Mole of HCl in solution 1 = 0.1645 mole

Mole of HCl in solution 2 = 0.195 mole

Total mole = 0.1645 + 0.195

<h3>Total mole = 0.3595 mole</h3>

  • Next, we shall determine the total volume of the final solution.

Volume of solution 1 = 0.658 L

Volume of solution 2 = 0.325 L

Total Volume = 0.658 + 0.325

<h3>Total Volume = 0.983 L</h3>

  • Finally, we shall determine the molarity of the resulting solution.

Total mole = 0.3595 mole

Total Volume = 0.983 L

<h3>Molarity =?</h3>

Molarity = mole / Volume

Molarity = 0.3595 / 0.983

<h3>Molarity = 0.366 M</h3>

Therefore, the molarity of the resulting solution is 0.366 M

Learn more: brainly.com/question/25342554

3 0
3 years ago
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