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g100num [7]
3 years ago
5

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

the base titrant volume as 2.04 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 20.95 mL. What volume, in mL, of base was required for the titration?
Chemistry
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

18.91 ml

Explanation:

Initial volume of base=2.04 ml

Final volume of base = 20.95 ml

Volume of base used= 20.95 - 2.04 = 18.91 ml

Note that the volume of base used is obtained as the difference between the final and initial volume of base, hence the answer given above.

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4 years ago
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djyliett [7]
Below are the choices:

a. −166 kJ/mol 
<span>b. 166 kJ/mol </span>
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<span>d. 1.66 × 10^5 kJ/mol
</span>
To calculate the activation energy of a reaction, we use the Arrhenius equation.  You may want to look it up to see how and why it works.  In the problem you posted, there are two temperatures and two rate constants.  After some rearranging and substitution of the Arrhenius equation, we have Ea = R T1 T2/(T1-T2) ln(k1/k2) = 8.314 J/mol K (600 K)(650 K)/(600 K-650 K) ln(2.7×10^-4 M^−1sec^−1/3.5×10^−3 M−^1sec^−1) = 166145 J/mol = 166 kJ/mol => choice b
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3 years ago
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1. sublimation

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3.melting  

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Answer:

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Explanation:

7 0
3 years ago
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Answer:

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Explanation:

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