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g100num [7]
3 years ago
5

uppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

the base titrant volume as 2.04 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 20.95 mL. What volume, in mL, of base was required for the titration?
Chemistry
1 answer:
OverLord2011 [107]3 years ago
5 0

Answer:

18.91 ml

Explanation:

Initial volume of base=2.04 ml

Final volume of base = 20.95 ml

Volume of base used= 20.95 - 2.04 = 18.91 ml

Note that the volume of base used is obtained as the difference between the final and initial volume of base, hence the answer given above.

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Burning 12.00 g of an oxoacid produces 17.95 g of carbon dioxide and 4.87 g of water. Consider that 0.25
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Answer: The molecular formula will be C_6H_6O_6

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Mass of CO_2 = 17.95 g

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For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

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For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

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Mass of H =  0.541 g

Mass of O = 6.57 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.89g}{12g/mole}=0.407moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.541g}{1g/mole}=0.541moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{6.57g}{16g/mole}=0.410moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.407}{0.407}=1

For H =\frac{0.541}{0.407}=1

For O = \frac{0.410}{0.407}=1

The ratio of C : H : O = 1: 1  : 1

Hence the empirical formula is CHO.

Hence the empirical formula is CHO

The empirical weight of CHO = 1(12)+1(1)+1(16)= 29 g.

If 0.25 moles has mass of 44.0 g

Thus 1 mole has mass of = \frac{44.0}{0.25}\times 1=176g

Thus molecular mass is 176 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{176g}{29g}=6

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