Answer:
A) 199.78 J
B) 9.292x10^14 J
C) 4.2x10^7 m/s
D) 0.65 m
E) 1.13x10^-8 sec
D) 2.94x10^-9 sec
Explanation:
mass of ball = 0.0580 kg
A)
If smashed at v = 83.0 m/s, KE is
KE = 0.5mv^2
= 0.5 x 0.0580 x 83.0^2
= 199.78 J
B) if returned at v = 1.79×10^8 m/s, KE will be
KE = 0.5mv^2
= 0.5 x 0.0580 x (1.79×10^8)^2
= 9.292x10^14 J
C) during Einstein's return, velocity of rabbit relative to players is
Vr = 2.21×108 m/s
Rabbit's velocity relative to ball = 2.21×10^8 - 1.79×10^8
= 4.2x10^7 m/s
D) the rabbit's speed approaches the speed of light so we consider relativistic effect. The rabbit's measured distance is
l = l°( 1 - v^2/c^2)
= 2.5(1 - 2.21/3)
= 2.5 x 0.26
= 0.65 m
E) according to the players, the time taken by the rabbit is
t = d/v = 2.5/ 2.21×10^8
= 1.13x10^-8 sec
F) the time for rabbit as measured by rabbit is relativistic
t = t°( 1 - v^2/c^2)
= 1.13x10^-8 (1 - 2.21/3)
= 1.13x10^-8 x 0.26
= 2.94x10^-9 sec
Answer:
7808 m/s
Explanation:
Find NE velocity after 60 s of acceleration in that direction:
= a t = 28.4 m/s^2 * 60 s = 1704 m/s
Vertical component = 1704 sin 45 = 1204.9 m/s
Horiz component = 1704 cos 45 = 1204.9 m/s
Add the two vertical components
6510 + 1204.9 = 7714.9 m/s = vertical velocity
Pythagorean theorem to find resultant of vertical and horiz v's
Vf ^2 = 1204.9^2 + 7714.9^2 0
Vf = 7808. m/s
Answer:
<h2>Potential difference across capacitors in parallel
</h2>
Two or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.
Answer:
3.33 Joules Per Second
Explanation:
Before finding the Power, we need to calculate the Work Done. The Work Done can be calculated using the formula:
WD = F × d
where F is the Magnitude of Force in <em>N</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>d is the Parallel Distance moved by the object in <em>m</em><em>.</em>
Hence, by Applying this formula, we get:
WD = (5)(20)
= 100 J
From here calculating Power is simple as it is the Rate of Work Done. Hence,
Power = 100/30
= <u>3</u><u>.</u><u>3</u><u>3</u><u> </u><u>J</u><u>/</u><u>s</u>
Therefore, the power put out is <u>3</u><u>.</u><u>3</u><u>3</u><u> </u><u>J</u><u>o</u><u>u</u><u>l</u><u>e</u><u>s</u><u> </u><u>p</u><u>e</u><u>r</u><u> </u><u>S</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>.</u>