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Dafna1 [17]
2 years ago
11

A student designs an experiment where he takes a small wood car with 1.0 inch diameter wheels and rolls it down a ramp. The stud

ent measures the speed of the car when it reaches the bottom of the ramp. The student then takes a small plastic car with 1.5 inch diameter wheels and repeats the process. Finally, the student takes a small metal car with 2.0 inch diameter wheels and repeats the process a final time. The student notes that the metal car had the fastest speed at the bottom of the ramp
Physics
1 answer:
Dvinal [7]2 years ago
3 0
The answer is none of the above
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Please help me out! Thanks! (:
ElenaW [278]

X=Ft is a possible equation for X because by using SI units its final term became Kg metre per second

3 0
3 years ago
A 64kg skateboarder on a 2.0kg skateboard is on top of a ramp with a vertical height of 5.0 m what is the skateboarders maximum
scoray [572]
The maximum kinetic energy will be equal to maximum potential energy thus the potential energy will be
mgh = 66*10*5 = 3300 j
4 0
2 years ago
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What's the way to building a time machine and I will reward you beautifully.DENY PHYSICS YOUNG JEDI
quester [9]
Easy brother. You just need some luck.

Inside every black hole is a time machine that allows you to turn back time or go forward and teleport to any empty space in the universe. However to do so you need to get inside the black hole without dieing.

To do so you must make the hardest and lightest box you can make, fill it with a very dense kind of air that will allow you to breathe but not move. Then seal yourself In the box.
Get someone to throw you in the black hole. And if you come back alive give me a Brainliest answer ;)
4 0
3 years ago
How much would your 20.0-kg dog weigh on Neptune?
Helga [31]

Answer:

22.73 kg

Explanation:

7 0
3 years ago
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A 110 kg crate is pulled along a level surface by an engine. The coefficient of kinetic friction between the crate and the surfa
Leno4ka [110]

Answer:

Net power will be 1150.637 watt

Explanation:

We have given mass of the crate m = 110 kg

Coefficient of friction \mu =0.585

Acceleration due to gravity g=9.8m/sec^2

Constant speed v=7.59m/sec

Force applied F=ma=110\times 7.59=834.9N

Frictional force f=\mu mg=0.585\times 110\times 9.8=630.63N

So net force =834.9-630.6=204.3N

Power is given by P=Fv=204.3\times 7.59=1550.637Watt

So net power will be 1550.637 watt

3 0
3 years ago
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