Answer:
6.45×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 97.3 MHz
Energy (E) =?
Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:
1 MHz = 1×10⁶ Hz
Therefore,
97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz
97.3 MHz = 9.73×10⁷ Hz
Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.
Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:
Frequency (f) = 9.73×10⁷ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 9.73×10⁷
E = 6.45×10¯²⁶ J
Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J
In Longitudinal waves, particles of the medium vibrate around their mean positions. Their amplitude of vibration is in the direction of the propagation of the wave. In transverse wave of longitudinal wave, <em>the wavelength is always the distance between two particles which are in the same phase.</em>
If we take pressure waves, (sound waves), we have pressure variations created by sound wave along its path. Pressure is maximum at compression regions and pressure is minimum at rarefaction region. In between the two, pressure of air remains as the pressure when there is no wave.
<em>The wave length is then the distance between two consecutive rarefactions or two consecutive compression regions.</em>
<em>It is also the distance traveled by the wave in one time period.</em> Time period is the time the particles in the medium take to vibrate towards the end, turn back to reach the other end of their oscillation and then reach back their position.
Answer:
Explanation:
Impossible to say without knowing how high point D is.
If we ignore friction, the energy converted from potential energy will exist as kinetic energy.
let d be the height in meters of point D "in the air"
mg(19 - d) = ½mv²
m is common so divides out
g(19 - d) = ½v²
v = √(2g(19 - d))
no sense in making g any more precise than the height. g = 9.8
v = √(2(9.8)(19 - d))
v = √(19.6(19 - d))
Answer:
Energy, 
Explanation:
It is given that,
The MRI (Magnetic Resonance Imaging) body scanners used in hospitals operate at a frequency of 400 MHz,
We need to find the energy for a photon having this frequency. The energy of a photon is given by :
So, the energy of the photon is 
. Hence, this is the required solution.
