I would say the answer is Pangaea. I got this answer but google searching "all land" means what... and the 3rd or 4th one down it says Answers.com
But i worn you answers.com is a very slow sight...
Hope it helps
and please mark me as brainiest
Answer:
La potencia de la bombilla es de 1056 W.
Explanation:
La potencia de la bombilla se puede calcular usando la siguiente ecuación:

En donde:
P: es la potencia
I: es la corriente = 2,4 A
V: es la diferencia de potencial = 440 V
Entonces, la potencia es:

Por lo tanto, la potencia de la bombilla es de 1056 W.
Espero que te sea de utilidad!
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Answer:
Spring's displacement, x = -0.04 meters.
Explanation:
Let the spring's displacement be x.
Given the following data;
Mass of each shrew, m = 2.0 g to kilograms = 2/1000 = 0.002 kg
Number of shrews, n = 49
Spring constant, k = 24 N/m
We know that acceleration due to gravity, g is equal to 9.8 m/s².
To find the spring's displacement;
At equilibrium position:
Fnet = Felastic + Fg = 0
But, Felastic = -kx
Total mass, Mt = nm
Fg = -Mt = -nmg
-kx -nmg = 0
Rearranging, we have;
kx = -nmg
Making x the subject of formula, we have;

Substituting into the formula, we have;


x = -0.04 m
Therefore, the spring's displacement is -0.04 meters.
The throttle regulates the power and/or of the engine. If the operator will release the throttle lever, the PWC will remain going straight ahead. Even if the operator will attempt to go right, the PWC will continue to go forward.