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tekilochka [14]

3 years ago

6

Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; both students move away from each

other. What law of motion is this. (Newton's laws)

1 answer:

Hatshy [7]3 years ago

7 0

Answer:

forcing in act

Explanation:

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The block slides on a horizontal frictionless surface. The block has a mass of 1.0kg and is pushed 5.0N at 45°. What is the magn

Firlakuza [10]

Answer:

$3.5\:\mathrm{m/s^2}$

Explanation:

Newton's 2nd law is given as $\Sigma F = ma$ .

To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.

Using trigonometry to find the horizontal component of the force:

$\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}$

Use this horizontal component of the force to solve for for the acceleration of the object:

$\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}$

8 0

2 years ago

A carrot hangs from the ceiling by a rope,

valentina_108 [34]

Answer: Diagram B

Explanation:

A free body diagram shows the forces acting on an object in a certain scenario.

In this scenario there are two forces acting on the carrot: the Tension force (Ft) from the rope that the carrot is hanging from and Gravitational force(Fg) which is pulling the carrot to the Earth.

The diagram depicting this is diagram B.

7 0

2 years ago

Read 2 more answers

Why do people tend to cup their hands around listeners' ears when whispering to them? A) A cupped hand makes the sound echo so t

WITCHER [35]

C. Hope this helps you!

6 0

3 years ago

Read 2 more answers

1. A large turbine has an initial angular momentum of 6700 kgm^2/s. A storm is rolling in and the wind picks up. 8 seconds later

LekaFEV [45]

Answer:

262.5 Nm

Explanation:

Torque is the rate of change of angular momentum.

Hence, we have

$\tau = \dfrac{\Delta L}{t}$

Δ<em>L</em> is the change in angular momentum.

Using values in the question,

$\tau = \dfrac{8800-6700 \text{ kg m}^2\text{/s}}{8\text{ s}} = 262.5 \text{ Nm}$

4 0

3 years ago

A wire with length 3.5 m and mass 0.03 kg is aligned horizontally and connected by conducting loops to two vertical frictionless

Sindrei [870]

Answer:

Current flowing in the wire is 1680 A

Explanation:

It is given length of wire l = 3.5 m

Mass of the wire m = 0.03 kg

Magnetic field B = 0.00005 Tesla

Acceleration due to gravity $g=9.8m/sec^2$

Mg force acting on the wire will be equal to Lorentz force acting on the wire.

Therefore $mg=IBl$

$0.03\times 9.8=I\times 0.00005\times 3.5$

$I=1680A$

Therefore current flowing in the wire is 1680 A

6 0

3 years ago