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Fittoniya [83]
3 years ago
8

Lin ran 29 meters in 10 seconds. she ran at a constant speed. At this rate, how far can she run in 1 minute

Mathematics
2 answers:
yaroslaw [1]3 years ago
5 0
174 meters in 1 minute.

If we take 29m and divide it by 10s, we get a value of 2.9. To find how much she can run in 1 minute, just take 60(secs) and multiply by 2.9.
scoundrel [369]3 years ago
3 0

Answer:

2.9 per second

Step-by-step explanation:

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Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

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3 years ago
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