Question

Triangle ABC is reflected over the x-axis. У C(5, - 1) | A(0, - 2) -3 -4 B(2, - 4) 5 -6 What are the vertices of AA'B'C '?

Answer 1

Answer:

The vertices of the triangle A'B'C' are $A'(x,y) =(0,2)$, $B'(x,y) = (-2,4)$ and $C'(x,y) = (-5,1)$, respectively.

Step-by-step explanation:

Vectorially speaking, the reflection of a point over the x-axis is defined by the following expression:

$P'(x,y) = P(x,y) -2\cdot P(x,y)$

$P'(x,y) = -P(x,y)$ (1)

Where:

$P(x,y)$ - Original point.

$P'(x,y)$ - Reflected point.

If we know that $A(x,y) = (0,-2)$, $B(x,y) = (2,-4)$ and $C(x,y) = (5,-1)$, then the vertices of the triangle A'B'C':

$A'(x,y) =(0,2)$, $B'(x,y) = (-2,4)$, $C'(x,y) = (-5,1)$

The vertices of the triangle A'B'C' are $A'(x,y) =(0,2)$, $B'(x,y) = (-2,4)$ and $C'(x,y) = (-5,1)$, respectively.