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Paha777 [63]
4 years ago
6

An isosceles triangle has a base 9.2 units long. If the congruent side lengths have measures to the first decimal place, what is

the shortest possible length of the sides?

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
3 0

Question:

An isosceles triangle has a base of 9.6 units long. If the congruent side lengths have measures to the first decimal place, what is the possible length of the sides? 9.7, 4.9, or 4.7

Answer:

4.9 is the shortest possible length of the sides.

Step-by-step explanation:

Given:

The base of the triangle base  =   9.2 units

To Find:

The shortest possible length of the sides = ?

Solution:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

So According to the theorem

x+x > 9.6

2x > 9.6

x > \frac{9.6}{2}

x > 4.8

In the given option 4.9 is the shortest length greater than 4.8 that can be possible.

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Answer:

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Step-by-step explanation:

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A cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shif
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We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is \frac{7\pi}{12}. The graph of the function does not show a phase shift. We are asked to write the equation of our function.

We know that general form a cosine function is y=A\cos(b(x-c))-d, where,

A = Amplitude,

\frac{2\pi}{b} = Period,

c = Horizontal shift,

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The equation of parent cosine function is y=\cos(x). Since function is reflected about x-axis, so our function will be y=-\cos(x).

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