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Paha777 [63]
4 years ago
6

An isosceles triangle has a base 9.2 units long. If the congruent side lengths have measures to the first decimal place, what is

the shortest possible length of the sides?

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
3 0

Question:

An isosceles triangle has a base of 9.6 units long. If the congruent side lengths have measures to the first decimal place, what is the possible length of the sides? 9.7, 4.9, or 4.7

Answer:

4.9 is the shortest possible length of the sides.

Step-by-step explanation:

Given:

The base of the triangle base  =   9.2 units

To Find:

The shortest possible length of the sides = ?

Solution:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

So According to the theorem

x+x > 9.6

2x > 9.6

x > \frac{9.6}{2}

x > 4.8

In the given option 4.9 is the shortest length greater than 4.8 that can be possible.

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if PQ || RS and the slope of PQ= x-1/4 and the slope of RS is 3/8 then find the value of x justify algebraically and numerically
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The value of x is 5/8.

<u>Step-by-step explanation</u>:

Given,

  • The lines PQ and RS are parallel to each other.
  • slope of PQ= x-1/4
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The slopes of parallel lines are equal.

slope of PQ = slope of RS

⇒ x-1/4 = 3/8

⇒ (4x-1)/4 = 3/8

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⇒ 32x-8 = 12

⇒ 32x = 20

x = 20/32

x = 5/8

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Sergio039 [100]

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