Is the water line of boat when someone boards or leaves it.
Answer:
The change in entropy is -1083.112 joules per kilogram-Kelvin.
Explanation:
If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (
), in joules per gram-Kelvin, by the following model:
(1)
Where:
- Mass, in kilograms.
- Specific heat of water, in joules per kilogram-Kelvin.
, 
- Initial and final temperatures of water, in Kelvin.
If we know that 
, 
, 
and 
, then the change in entropy for the entire process is:
The change in entropy is -1083.112 joules per kilogram-Kelvin.
Answer:
Lots of things here
Explanation:
Ammonia structure is written as NH3
carbon monoxide is CO
make bonds between O2, so there is 2 oxygen atoms per group,
anything with multiple elements bonded is a compound, thus your answer for carnon monoxide isnt correct, it should be CO for written and it is a compound. Fix your formula for ammonia and also max a bond between those two oxygens because it is O2 not O,
Your structure for SO2 is improper aswell, there are only 3 elements in this molecule, and usually the one out in front of the molecule is the central atom (except hydrogen). So it would go O-S-O for the structure, with only two bonding groups.
Hydrochloric Acid (HCl) is a strong acid when it is present in the concentrated form but when it is dissolved in water (
) the atoms of this compound dissociates into its respective ions as shown below:
When we add HCl to any complex in its concentrated form the complex does not react at all but when its diluted to 6M and is kept for many hours, the complex reacts slowly. For eg:
![[Co(NH_3)_6]^3^+(aq.) + HCl(aq.) \rightarrow [Co(NH_3)_5Cl]^2^+(aq.) + NH_4^+ (aq.)](https://tex.z-dn.net/?f=%5BCo%28NH_3%29_6%5D%5E3%5E%2B%28aq.%29%20%2B%20HCl%28aq.%29%20%5Crightarrow%20%20%5BCo%28NH_3%29_5Cl%5D%5E2%5E%2B%28aq.%29%20%2B%20NH_4%5E%2B%20%28aq.%29)
As seen from the above reaction it can be seen the positive charge on the complex is reduced by 1 unit because one 
ion gets attached to the centre metal atom, therefore we can conclude that the charge on complex gets reduced by 1 unit when HCl reacts with the complex.
