So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+
Answer:<em>if u change the number of neutrons u will .get an isotope of the same element. </em>
Explanation: <em>neutron can make an atom radioactive</em>
Answer:
V₂ = 123.6 L
Explanation:
According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,
P₁ V₁ = P₂ V₂ ----- (1)
Data Given;
P₁ = 103 kPa
V₁ = 30 L
P₂ = 25 kPa
V₂ = ?
Solution:
Solving equation 1 for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (103 kPa × 30 L) ÷ 25 kPa
V₂ = 123.6 L
Result:
As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
Answer:
10.875L
Explanation:
The problem here is a simple conversion. The conversion is from gal to liters Liter is a SI unit for recording volume as stated in the problem.
Given that:
1 gallon of water = 3.75L
2.90 gallon will be 2.9 x 3.75; 10.875L
