All categories

3 years ago

A long distance runner starts at the beginning of a trail and runs at a rate of

Mathematics

1 answer:

kipiarov [429]3 years ago

8 0

Hello!

When the cyclist starts,the runner will have already ran 8 miles. We can write this equation below, where h represents the hours run since the cyclist took off.

14h=8+4h

Let's move the variables onto one side. First we subtract 4h from both sides.

10h=8

Now we divide both sides by 8.

1.25

As you can see, it will take 1.25 hours for the cyclist to overtake the runner.

I hope this helps!

You might be interested in

HELP MATH ASAP! MARKING BRANLIST

qwelly [4]

Answer:

-4/3

Step-by-step explanation:

Use the slope formula:

$\frac{y2-y1}{x2-x2}$

-4 - 12/ 13 - 1

-16/12

Simplifies to -4/3

8 0

3 years ago

Packard Corporation reported pretax book income of $501,400. Included in the computation were favorable temporary differences of

Alik [6]

Answer:

The answer is: The amount of: $ 330,700.

Step-by-step explanation:

Packard Corporation had a pre-tax book income of $ 501,400. Then he has a favorable amount of $ 11,400 that he would therefore add, and unfavorable amounts of $ 101,400 and $ 80,700 that would be subtracted. The current expense or benefit of the corporation's income tax would be: 501,400 + 11,400 - 101,400 - 80,700 = $ 330,700.

The answer is: The amount of: $ 330,700.

5 0

3 years ago

Write the equation in slope intercept form with a slope of 3/4 and passes through (-4,-5)

attashe74 [19]

Answer:Use the slope −2 and the point (−4,−5) to find the y-intercept.

y=mx+b

⇒−5=(−2×−4)+b

⇒−5=8+b

⇒b=−13

Write the equation in slope intercept form as:

y=mx+b

⇒y=(−2)x−13

Hence, the equation of the line is y=−2x−13.

Step-by-step explanation:

Please make me brainliest :)

7 0

3 years ago

382215 HELP ME WITH THIS QUESTION!

Rom4ik [11]

Answer:

T'= (-4,-3)

U'= (5,-3)

V'= (-5,2)

Please mark me brainlest

5 0

3 years ago

Write the explicit formula for the geometric sequence 2, 8, 32, 128

Alja [10]

The first term, a, is 2. The common ratio, r, is 4. Thus,

a_(n+1) = 2(4)^(n).

Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.

Try this instead:

a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.

The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.

3 0

3 years ago