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3 years ago

What is speedASAP who plss

Physics

2 answers:

solniwko [45]3 years ago

8 0

Answer:

Explanation:

Speed is a measurment that tells him much distance a body travels over a certain amount of time (usually measured in meters per second (m/c))

iren [92.7K]3 years ago

8 0

Is speed of a object

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Explain, using the particle theory of matter, how diffusion takes place.

marusya05 [52]

Explanation: When a pure substance's particle is moving from an area of high concentration to an area of lower concentration by occupying the spaces between the particles of another substance it is mixing or diffusing with. The particles of both the substances will mix or diffuse faster when the temperature is high.

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3 years ago

A climber using bottled oxygen accidentally drops the oxygen bottle from an altitude of 4500 m. If the bottle fell straight down

Trava [24]

Answer:

v= 300 m/s

Explanation:

Given that

altitude ,h= 4500 m

The mass ,m = 3 kg

Lets take acceleration due to gravity , g= 10 m/s²

The speed before impact at sea level = v

Initial speed ,u = 0 m/s

We know that

v²=u²+2 g h

v=final speed

u=initial speed

h=height

Now by putting the values in the above equation

v² = 0²+ 2 x 10 x 4500

v²=90000

v= 300 m/s

Therefore the speed at sea level will be 300 m/s.

3 0

3 years ago

What is physical quantity ? Give examples.

Dahasolnce [82]

Explanation:

physical quantity is any physical property that can be qualified that,is, be measured using numbers e.g mass, amount of substance,time and length

7 0

3 years ago

A military helicopter on a training mission is flying horizontally at a speed of 90.0 m/s when it accidentally drops a bomb (for

Elena-2011 [213]

Answer:

1) 10.1 s 2) 909 m 3) 90.0 m/s 4) -99m/s 5) just over the bomb.

Explanation:

In the vertical direction, as the bomb is dropped, its initial velocity is 0.
So, we can find the time required for the bomb to reach the earth, applying the following kinematic equation for displacement:

$\Delta y = \frac{1}{2}*a*t^{2} (1)$

where Δy = -500 m (taking the upward direction as positive).
a=-g=-9.8 m/s²
Replacing these values in (1), and solving for t, we have:

$t =\sqrt{\frac{2*\Delta y}{-g}} = \sqrt{\frac{2*(-500m)}{-9.8m/s2}} = 10.1 s$

The time required for the bomb to reach the earth is 10.1 s.

In the horizontal direction, once released from the helicopter, no external influence acts on the bomb, so it will continue moving forward at the same speed. that it had, equal to the helicopter.
As the time must be the same for both movements, we can find the horizontal displacement just as the product of this speed times the time, as follows:

$x = v_{0x} * t = 90.0 m/s * 10.1 s = 909 m.$

The horizontal component of the bomb's velocity is the same that it had when left the helicopter. i.e. 90 m/s.

In order to find the vertical component of the bomb's velocity just before it strikes the earth, we can apply the definition of acceleration, remembering that v₀ = 0, as follows:

$v_{f} = -g*t = -9.8 m/s2*10.1 s = -99 m/s$

If the helicopter keeps flying horizontally at the same speed, it will be always over the bomb, as both travel horizontally at the same speed.
So, when the bomb hits the ground, the helicopter will be exactly over it.

8 0

4 years ago

A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c

Jlenok [28]

Answer:

8962.5 N

Explanation:

From fundamental kinematics equations, acceleration, a is given by $a=\frac {v-u}{t}$ where v is final velocity, u is initial velocity and t is time