Ask question

Ask question

All categories

2 years ago

8

two identical steel balls mounted on wooden posts initially have different amounts of charge, one -14цC and the other +2цC. the

balls are allowed to touch and them are separated again. what is the final charge

1 answer:

larisa86 [58]2 years ago

4 0

-6 and -6 (each)

....

You might be interested in

A car travels along a straight line at a constant speed of 53.0 mi/h for a distance d and then another distance d in the same di

Shalnov [3]

A distance of d is covered with 53 mile/hr initially. Time taken to cover this distance t1 = d/53 hour Next distance of d is covered with x mile hours. Time taken to cover this distance t2 = d/x hours. We have average speed = 26.5 mile / hour

= Total distance traveled/ total time taken

= $\frac{2d}{\frac{d}{53}+\frac{d}{x}} = \frac{2}{\frac{1}{53}+\frac{1}{x} } = \frac{106x}{x+53}$

$26.5 = \frac{106x}{x+53} \\ \\ 79.5 x = 1404.5\\ \\ x = 17.67 miles/hour$

5 0

3 years ago

How does an understanding of plate motion help scientists

Arte-miy333 [17]

Answer:

advance in the understanding of cellular movement

Explanation:

All organisms are formed from cells, "understanding how cells are able to interact with other cells during development helps us understand how tissues and organs are established and, consequently, how the shape arises in embryos," explains Germán Reig

6 0

3 years ago

180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?

ale4655 [162]

Explanation:

Work done= MGH

180=m×10×3

180/30=m

m=6kg

4 0

2 years ago

A hot air balloon rising vertically is tracked by an observer located 3 miles from the lift-off point. At a certain moment, the

yuradex [85]

Answer:

$\frac{dy}{dt}=1.2\frac{mi}{min}$

Explanation:

We know that the tangent function relates the angle of the right triangle that forms the hot air balloon rising:

$tan\theta=\frac{y}{x}\\y=xtan\theta(1)$

Differentiating (1) with respect to time, we get:

$\frac{dy}{dt}=tan\theta\frac{dx}{dt}+xsec^{2}\theta\frac{d\theta}{dt}\\$

$\frac{dx}{dt}=0$ since x is a constant value. Replacing:

$\frac{dy}{dt}=3mi(sec^{2}\frac{\pi}{3})0.1\frac{rad}{min}\\\frac{dy}{dt}=1.2\frac{mi}{min}$

5 0

3 years ago

which form of radioactive decay would you be most likely to detect if it were happening in the room next to the one you are curr

aleksandrvk [35]

There are no options given in respect to the question and so it is not possible to choose. I would answer this question based on my knowledge and hope it satisfies you. he form of radio active decay that would be most likely detected by you if it were happening in the room next to the one you are currently standing in is gamma.

8 0

3 years ago