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3 years ago

11

A student wants to find the relationship between the diameter of several plastic disks and the circumference of each disk. Which

of these types of graphs should be constructed to determine this relationship?
A.
box-and-whisker plot
B.
pie graph
C.
scatterplot
D.
line graph

1 answer:

Helen [10]3 years ago

3 0

Answer:

the student ate the pie chart

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The standard reduction potentials for the Ag+|Ag(s) and Zn2+| Zn(s) half-cell reactions are +0.799 V and -0.762 V, respectively.

mihalych1998 [28]

<u>Answer:</u> The potential of the given cell is 1.551 V

<u>Explanation:</u>

The given chemical cell follows:

$Zn(s)|Zn^{2+}(0.125M)||Ag^{+}(0.240M)|Ag(s)$

<u>Oxidation half reaction:</u> $Zn(s)\rightarrow Zn^{2+}(0.125M)+2e^-;E^o_{Zn^{2+}/Zn}=-0.762V$

<u>Reduction half reaction:</u> $Ag^{+}(0.240M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.799V$ ( × 2)

<u>Net cell reaction:</u> $Zn(s)+2Ag^{+}(0.240M)\rightarrow Zn^{2+}(0.125M)+2Ag(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.799-(-0.762)=1.561V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Ag^{+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = ? V

$E^o_{cell}$ = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=0.125M$

$[Ag^{+}]=0.240M$

Putting values in above equation, we get:

$E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})$

$E_{cell}=1.551V$

Hence, the potential of the given cell is 1.551 V

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sveta [45]

Uhh I think d sorry if wrong ;-;

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if 105 grams burns completely

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What volume of oxygen at STP will be produced if the following reaction absorbed 275 kJ of heat?

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A foundry produces circular utility access hatches (manhole covers). Currently, 120 covers are produced in a 10-hour shift. If l

SOVA2 [1]

Answer:

14.4 covers/hr.

Explanation:

First, we need to identify how much covers are produced in 1 hour, which will be total produced divided by the total time:

covers/hr = 120/10

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If the production will be increased by 20%, it means that new production will be the initial one plus 20% (0.20) of it:

12 + 0.20*12 = 14.4 covers/hr.

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