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Lyrx [107]
3 years ago
5

When acetic anhydride is dissolved in water, it forms acetic acid according to the balanced chemical reaction shown below. calcu

late the theoretical yield (in grams of acetic acid, fw 60.05 g/mol) if 8.79 ml of acetic anhydride (fw 102.09 g/mol,
d. 1.08 g/ml) is used. you can assume that the water is present in excess?
Chemistry
1 answer:
melisa1 [442]3 years ago
6 0

2(CH3)2O3 + 2H2O   --->   4 CH3COOH  is the balanced equation.


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The volume of a sample of nitrogen is 6.00 liters at 35oC and 0.75 atm. What volume will it occupy at STP?
joja [24]
The  volume that  will  occupy  at STP  is  calculated   as  follows
by use  of ideal  gas  equation
that is  PV=nRT  where n  is  number of  moles  calculate  number of moles

n= PV/RT
p=0.75 atm
V=6.0  L
R = 0.0821  L.atm/k.mol
T=  35  +273= 308k
n=?

n=  (o.75  atm  x  6.0 L)/( 0.0821 L.atm/k.mol  x 308 k)=  0.178 moles

Agt  STP  1 mole=  22.4 L  what obout  0.178 moles

=  22.4  x0.178moles/ 1moles =3.98 L( answer C)
3 0
3 years ago
Please help me!!!!!!
Norma-Jean [14]

Answer:

17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3

4 0
3 years ago
10. A 38.0-g sample of NaOH is dissolved in water, and the solution is diluted to give a final
Sonbull [250]

Answer:

B.0.558M

Explanation:

M=n/L

n=m/Mm

Mm=NaOH

=23+16+1

=40g/mol

n=m/Mm

= 38/40

=0.95

M=n/L

=0.95/1.70

=0.558

8 0
3 years ago
Fred can create 20 animal balloons every 15 minutes. solve ratio table
DerKrebs [107]

The number of animal balloons created in 15 minutes = 20

The number of animal balloons created in 1 minute = \frac{20}{15}

So, the number of animal balloons created in 6 minutes = \frac{20}{15}\times 6 = 8

And, the number of animal balloons created in 45 minutes = \frac{20}{15}\times 45 = 60

So, the solved ratio table will be:

15.20

6.8

45.60



3 0
3 years ago
Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm3. If the combustion of t
maks197457 [2]

Answer:

The gases will expand until a volume of Vf= 10812 cm^3

Explanation:

Since the gas mixture is expanding at constant pressure

W=\int\limits^{Vf}_{Vi} {P} \, dV =P(Vf-Vi)

and therefore

Vf=W/P+Vi

knowing that 1 torr=133,32 Pa

p=635 torr * 133,322 Pa/torr * 1m^{3}/10^{6}cm^{3}=0,08466 J/ cm^{3}

therefore

Vf=912 J/(0,08466 J/cm^{3}) +40cm^{3} =10812 cm^{3}

8 0
3 years ago
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