Mai bought gas for her car.

lana [24]

Answer:

$42

Step-by-step explanation:

It's $42 because 11+44.50 is 54.50 and then you take out 6.25 twice because it's her and one friend to get 42 dollars. Hope this helps!

7 0

2 years ago

Para reformar la cocina de su caja Berta compro la semana pasada 2 cajas de plaquetas para el suelo y 4 de azulejos para la pare

Anvisha [2.4K]

Answer:

Caja de plaquetas = x = 30 €

Caja de azulejos = y = 35 €

Step-by-step explanation:

Deje que el costo de

Caja de plaquetas = x

Cuadro de mosaico = y

Por Berta

Para reformar su cocina, Berta compró la semana pasada 2 cajas de baldosas de plaquetas para el suelo y 4 cajas de baldosas para la pared por 200 €.

2x + 4y = 200 ...... Ecuación 1

Hoy

Hoy compré 2 cajas más de plaquetas y otras 2 de tejas por 130 €.

2x + 2y = 130 ..... Ecuación 2

Resolvemos usando el método de Eliminación

2x + 4y = 200 ...... Ecuación 1

2x + 2y = 130 ..... Ecuación 2

Restar la ecuación 2 de 1

2 años = 70

y = 70/2

y = 35 €

Resolviendo para x

2x + 4y = 200 ...... Ecuación 1.

2x + 4 × 35 = 200

2x + 140 = 200

2x = 200 - 140

2x = 60

x = 60/2

x = 30 €

el costo de

Caja de plaquetas = x = 30 €

Caja de azulejos = y = 35 €

6 0

3 years ago

Not easy help me please

Yuki888 [10]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

In the number line attached in my attachment,

The red line represents point :

$\dfrac{10}{2}$

The blue line represents point :

$\dfrac{ - 9}{2}$

I hope it helps ~

3 0

3 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

4 years ago

Help please me please help me

Vinil7 [7]

Answer: (3, 18)

Step-by-step explanation: Where the lines corss the x does not go over 10 so the only other option is a 3. If you cut the box hori in half in you mind, the top half being 15-20 and the bottom half bring 10-14, then you can see the lines cross on the top half. Meaning it’s at 18 not 12.

3 0

3 years ago