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Paladinen [302]
3 years ago
13

2.30+2.50+2.75+2.00​

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

9.55 hope this helps :)

Step-by-step explanation:

  1

  2.30

  2.50

+ 2.75

  2.00

-----------

  9.55

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Which expression represent the approximate length of BC HEEEEELLLLPPP!!!
Bumek [7]

Answer:

A

Step-by-step explanation:

Using the Sine rule in Δ ABC

\frac{sinA}{BC} = \frac{sin38}{AB} , substitute values

\frac{sin66}{BC} = \frac{sin38}{3} ( cross- multiply )

BC sin38° = 3 sin66° ( divide both sides by sin38° )

BC = \frac{3sin66}{sin38} → A

5 0
3 years ago
Place the following fractions in order from least to greatest.<br><br> -2/3, 21/4, 11/12, -5/8
TEA [102]

Answer:

-2/3, -5/8, 11/12, 21/4

Step-by-step explanation:

6 0
3 years ago
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Find the value of x. The diagram is not drawn to scale.
lidiya [134]
116+y=180(sum of angles in a straight line)
y=180-116
y=64

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x+64+125+72=540
x+125+136=540
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x=540-261
x=79
7 0
3 years ago
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Plz help me solve this pre calc problem, I have to condense using the properties of log
Ahat [919]

Given:

\log \left(x^{2}\right)+\log \sqrt{x^{3}+1}

To find:

The condense of the logarithmic function.

Solution:

\log \left(x^{2}\right)+\log \sqrt{x^{3}+1}

Apply log rule:

\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)

Using the log rule:

\log _{10}\left(x^{2}\right)+\log _{10}(\sqrt{x^{3}+1})=\log _{10}\left(x^{2} \sqrt{x^{3}+1}\right)

\log \left(x^{2}\right)+\log \sqrt{x^{3}+1}=\log \left(x^{2} \sqrt{x^{3}+1}\right)

7 0
4 years ago
Figure 1 is a square pyramid. Figure 2 is a right triangular prism.
amm1812

Answer:

the answer is

The surface area of Figure 1 is <u>10.2</u> square centimeters <u>Less</u> than the surface area of Figure 2.

Step-by-step explanation:

Figure 1

area of a square = s2

=9squared

=81 sq cm

area of triangle = 1/2 bh

=1/2 (9cm) (14cm)

=63 sq. cm

find surface area

SA = 81 sq. cm + 4(63 sq. cm)

SA = 81 sq. cm + 252 sq. cm

SA = 333 sq. cm

Figure 2 Calculation

area of rectangle = lw

a = (12cm) (8 cm)

a = 96 sq. cm

area of triangle = 1/2 bh

=1/2 (8 cm) (6.9 cm)

= 27.6 sq. cm

total surface are of figure 2

SA = 3 (96 sq.cm) + 2 (27.6 sq. cm)

SA = 288 sq. cm + 55.2 sq. cm

SA = 343.2 sq. cm

find the difference between figure 1 and figure 2

343.2 sq. cm - 333 sq. cm = 10.2 sq. cm

5 0
3 years ago
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