<u>Answer:</u> The spacecraft traveled 345 km during the given time.
<u>Explanation:</u>
To calculate the distance of spacecraft, we use the equation:

We are given:
Velocity = 2.3 km/sec
Time = 2.5 mins = 150 sec (Conversion factor: 1 min = 60 sec)
Putting values in above equation, we get:

Hence, the spacecraft traveled 345 km during the given time.
Three examples of environmental, industrial and bio-chemistry are listed below:
- Environmental chemistry: Contamination, Atmospheric Deposition, and Soil Pollution.
- industrial chemistry: industrial inorganic chemicals, industrial organic chemicals, and agricultural chemicals
- bio-chemistry: genetic, immunology, and enzymology
<h3>Meaning of Chemistry</h3>
Chemistry can be defined as a branch of science which is concerned with the substances matter is composed of, their properties and reactions,
Chemistry also deals with the use of such reactions to form new substances.
In conclusion, Three examples of environmental, industrial and bio-chemistry are listed anove
Learn more about chemistry: brainly.com/question/24419453
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Answer:
2.1 atm
Explanation:
We are given the following variables to work with:
Initial pressure (P1): 2.5 atm
Initial temperature (T1): 320 K
Final temperature (T2): 273 K
Constant volume: 7.0 L
We are asked to find the final pressure (P2). Since volume is constant, we want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:

We can rearrange the law algebraically to solve for
.

Substitute your known variables and solve:

Attractive force e.g - magnetic force, electric force, electrostatic force and gravitational force.
Answer:
Ksp = [ Cu+² ] [ OH-] ²
molar mass Cu(oH )2 ==> M= 63.546 (1) + 16 (2) + 1 (2) = 97.546 g/mol
Ksp = [ Cu+² ] [ OH-] ²
Ksp [ cu (OH)2 ] = 2.2 × 10-²⁰
|__________|___<u>Cu</u><u>+</u><u>²</u><u> </u>__|_<u>2</u><u>OH</u><u>-</u>____|
|<u>Initial concentration(M</u>)|___<u>0</u>__|_<u>0</u>______|
<u>|Change in concentration(M)</u>|_<u>+S</u><u> </u>|__<u>+2S</u>__|
|<u>Equilibrium concentration(M)|</u><u>_S</u><u> </u><u>_</u><u>|</u><u>2S___</u><u>|</u>
Ksp = [ Cu+² ] [ OH-] ²
2.2 ×10-²⁰ = (S)(2S)²= 4S³
![s = \sqrt[3]{ \frac{2.2 \times {10}^{ - 20} }{4} } = 1.8 \times {10}^{ - 7}](https://tex.z-dn.net/?f=s%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B2.2%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%2020%7D%20%7D%7B4%7D%20%7D%20%20%3D%201.8%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%207%7D%20)
S = 1.8 × 10-⁷ M
The molar solubility of Cu(OH)2 is 1.8 × 10-⁷ M
Solubility of Cu (OH)2 =

<h3>
Solubility of Cu (OH)2 = 1.75428 × 10 -⁵ g/ L</h3>
I hope I helped you^_^