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Flauer [41]
3 years ago
10

1. The more velocity an object has the harder it is to slow it down, speed it up, or turn it.

Physics
1 answer:
deff fn [24]3 years ago
8 0

Answer:

The more velocity an object has the harder it is to slow it down

Explanation:

slow it down

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What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?
krok68 [10]

Answer: m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }

It is given that:

Density of material =ρ

radius of inner spherical shell = r_1

radius of outer spherical shell=r_2

we know that the volume of sphere is \frac{4}{3}\pi r^{3}

Volume of the given spherical shell = \frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }


6 0
3 years ago
A body starting from rest and moves with uniform acceleration. The velocities of the body are 40 m/s at the 4th second and 60 m/
Sergeeva-Olga [200]

Answer:

GIVEN

u is 40m/s and v=60m/s

time is 4s

therefore acceleration =60-40/4

=20/4=5m/s^2

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8 0
3 years ago
There are four stages in an economic recovery. In which order do these stages occur
Klio2033 [76]

The answer is 2,1,3,2

1. increased production 2. rising demand (occurs twice) 3. increased hiring

hope this helps :)

7 0
4 years ago
Let’s say you pour an ounce of water from a class into a bowl. Does the water’s mass change?
ch4aika [34]

Answer:

No. If you take 5$ from your wallet and place on the shelf, does it change its value - No. So if you take the water from class(does not matter how much) and pour all of it somewhere else, it doesn't change its mass, yet it changes its shape.

5 0
3 years ago
A radio wave has a frequency of 4.40 × 108 hz. what is the energy (in j) of one photon of this radiation? enter your answer in s
LiRa [457]
The energy of a single photon is given by
E=hf
where 
h=6.6 \cdot 10^{-34} Js is the Planck constant
f is the frequency of the wave (of the photon)

In our problem, the radio wave has a frequency of f=4.40 \cdot 10^8 Hz, so if we put this value into the previous formula, we can find the energy of a single photon of this electromagnetic wave:
E=hf=(6.6 \cdot 10^{-34} Js)(4.40 \cdot 10^8 Hz)=2.9 \cdot 10^{-25} J
7 0
3 years ago
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