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Maurinko [17]
3 years ago
7

Pls help ...........

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0
D ( -3.5 , -1) O ( -3.5 , -3.5) G ( -3.5 , 0)
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This is my last day of school so i need help to finish this'
podryga [215]
The answer it’s a. Pretty sure if not sorry
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3 years ago
Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

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A sample with which of these variances has a standard deviation that is greater than the variance?
White raven [17]
Since the standard deviation is the square root of variance. The only times where the standard deviation is greater than the variance is when the variance is between the values 0 and 1 exclusively. For example, the square root of 0.25 is 0.5. 
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Answer:

Step-by-step explanation:

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Answer:

Step-by-step explanation:

If x is -1, then the point on the parabol is (-1,4)

If x is 0, then the point on the parabol is (0,-2)

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