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2 years ago

First come first served brainiest:)

Mathematics

1 answer:

navik [9.2K]2 years ago

4 0

Answer:

flush f Cass g get chicken snitched to-do racism Ifb o'clock

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iragen [17]

A. (8,4) because you can tell in the second pattern

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3 years ago

Help me please 2-4x=x+16

Elina [12.6K]

2-4x=x+16
-5x=13

x=-2.6

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3 years ago

Using order of operations to simplify what is (5+22)x(35-27)+6x6

tatyana61 [14]

(5+22)x(35-27)+6x6
27 (35-27)+6x6
27x8+6x6
27x7+36
216+36
=252

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3 years ago

2.75+0.003+0.158 it has been a while since I have had a math class. I forgot how I am suppose to line the decimal points up. Tha

g100num [7]

2.750
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2 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

6 0

3 years ago

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