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skelet666 [1.2K]
3 years ago
7

When you walk across the ground and push on it with your feet...

Physics
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

The ground pushes back on your feet with equal force.

Explanation:

Newton's Laws of Motion

ladessa [460]3 years ago
3 0
The ground pushes back on your feet with equal force
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Concrete is pumped from a cement mixer to the place it is being laid, instead of being carried in wheelbarrows. The flow rate is
max2010maxim [7]

Answer:

a. 2.4 ×109  N ⋅ m2/s

b. 48.3 N⋅s /m2  

c. 8.00×104W

Explanation:

See Attached file for explanation

3 0
3 years ago
Zero field spot for opposite unequal charges
xz_007 [3.2K]

Answer:

The zero field location has to be on the line running between the two point charges because that's the only place where the field vectors could point in exactly opposite directions. It can't be between the two opposite charges because there the field vectors from both charges point toward the negative charge.

7 0
3 years ago
Which phrase describes a planet’s period of rotation? A. the shape of its orbit B. its tilt relative to the sun C. one complete
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C. one complete spin on its axis because the rotation is referring to the planet's period of rotation. D is called a revolution. B determines the seasons on the planets. A is called an ellipse.
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3 years ago
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One end of a steel rod of radius R = 10 mm and length L = 80cm is held in a vise. A force of magnitude F = 60kN is then applied
Alexandra [31]

Answer: 1.91*10^8 N/m²

Explanation:

Given

Radius of the steel, R = 10 mm = 0.01 m

Length of the steel, L = 80 cm = 0.8 m

Force applied on the steel, F = 60 kN

Stress on the rod, = ?

Area of the rod, A = πr²

A = 3.142 * 0.01²

A = 0.0003142

Stress = Force applied on the steel/Area of the steel

Stress = F/A

Stress = 60*10^3 / 0.0003142

Stress = 1.91*10^8 N/m²

From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²

8 0
3 years ago
A 4kg ball moving at 8m\sec
Llana [10]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
8 0
3 years ago
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