Answer:
B. the force of on the truck due to the collision is exactly equal to the force on the car.
Explanation:
At the time of collision between two objects of unequal or equal masses two forces emerge at the point of collision .They are called action and reaction force . According to third law of Newton , they are equal . So in the instant case of collision between car and truck , force on both of them will be equal.
Answer:
Average speed: 86 km/h
Explanation:
Driving from San Antonio to Houston:
1st. half time: 54km/h
2nd. half time: 118 km/h
Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]
Driving way back:
1st. half time: 54km/h
2nd. half time: 118 km/h
Average speed = [tex] \frac{54 \frac{km}{h}+ 118 \frac{km}{h} }{2}=86 \frac{km}{h} [\tex]
As in both routes we have the same average speed, then the average speed for the whole trip is 86 km/h
<span>In order for the results to be valid, the dependent variable can only be affected by the independent variable, so somethings need to be kept constant. The things that need to be kept constant are called controlled variables.</span>
Answer:
9.75 x 10^4 J
Explanation:
Work done, W = 9.75 x 10^4 J
According to the work energy theorem, the change in kinetic energy is equal to the work done by all the forces.
So, here work done is 9.75 x 10^4 J so the change in kinetic energy is 9.75 x 10^4 J.
Answer:
The work done on the suitcase is, W = 600 J
Explanation:
Given,
The average force exerted by Jose on his suitcase, F = 60 N
Jose carried the suitcase to a distance, S = 10 m
The work done on the suitcase is given by the relation
<em>W = F x S</em>
Substituting the given values in the above equation,
W = 60 N x 10 m
= 600 J
Hence, the work done on the suitcase is, W = 600 J
