Ans:
12500 N/C
Explanation:
Side of square, a = 2.42 m
q = 4.25 x 10^-6 C
The formula for the electric field is given by
where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges
According to the diagram
BD = 
where, a be the side of the square
So, Electric field at B due to charge at A
EA = 6531.32 N/C
Electric field at B due to charge at C
Ec = 6531.32 N/C
Electric field at B due to charge at D
ED = 3265.66 N/C
Now resolve the components along X axis and Y axis
Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C
Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C
The resultant electric field at B is given by
E = 12500 N/C
Explanation:
If you are choosing to get a digital photo album it can come with the advantages like, it’s more economically friendly because you’re not having to print out pictures. But it’s disadvantage is that you can lose it easily or accidentally delete it some way. You also have a choice of a physical photo album, it’s advantages are that you won’t lose it as easily and they might last longer than a digital one’s. It’s disadvantage though is that with all the pictures and the book to keep the pictures in takes a lot from the economy. A solution to the digital photo album is to save in on a hard drive or something like that so you can keep it without having to worry about it being deleted as easily. The solution with the physical photo album is that you could get a photo holder that you can slide picture into pockets because it will keep the pictures from damage as well as using less paper products.
you can read over it and change things i might have done wrong and if i completely missed the point of this i’m sorry and hope you have a good day/night. (also it’s 6 sentences)
Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J
Answer:
Solution
Explanation:
Solution:-
- The direction of motion of bus and car can be denoted by velocity vectors ( v1 and v2 ) respectively.
- On a page draw the velocity vector v1 vertically up denoting the direction of motion of bus from origin
- Similarly,draw the velocity vector v1 horizontally left denoting the direction of motion of car from origin.
- The force exerted by the car-bus interaction is always in the direction of motion.
- The force exerted by the bus is parallel to velocity vector as F1 and force exerted by the car is parallel to velocity vector as F2.
- The vector addition of of the two forces ( F1 and F2 ) will tell us the direction and magnitude of resultant force due to car-bus interaction.
- The resultant force will cause the car to be pushed off the road in the direction shown in the diagram.
