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Kryger [21]
3 years ago
14

What is the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mM?

Biology
1 answer:
Doss [256]3 years ago
8 0

Answer:

50 micro mol/min

Explanation:

So, we have the following parameters which are going to help us in solving this particular Question or problem;

=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.

=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.

So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;

Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.

Initial velocity for the wild type enzyme = 50 micro mol/min.

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The time that it would take for the population to double is about 7 years.

<h3>What is population?</h3>

The population of an area refers to the number if people that live in that particular area per time. The life expectancy of a population is increased by adequate sanitation. When there is over  population in an area, it can lead to malnutrition and decreased food production.

A density dependent factor that affects population growth is disease transmission. The countries with the highest populations in the world do not necessarily have the fastest population growth. One factor that has led to lower fertility rates in Europe and North America is educational opportunity for women.

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Using;

P= Poe^rt

P = 74,000

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r = 0.1

Hence;

74,000 = 37,000e^0.1t

74,000/37,000 = e^0.1t

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Learn more about population growth: brainly.com/question/12228859

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