Question

What is the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mM?

Answer 1

Answer:

50 micro mol/min

Explanation:

So, we have the following parameters which are going to help us in solving this particular Question or problem;

=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.

=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.

So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;

Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.

Initial velocity for the wild type enzyme = 50 micro mol/min.