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Amanda [17]
3 years ago
6

A person walks 1/5 miles in 1/15 hour. The persons speed is _ miles per hour. whats the speed.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
8 0

Answer:

3 miles

Step-by-step explanation:

you walk 1/5 miles for 1/15 hour, the just do 1/5 time 15 = 15/5 =3

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A scientest is studying a new super bacteria that is threatening to cause an outbreak. On the first day, there were 5 organisms
ElenaW [278]

Answer:

C. 125

Step-by-step explanation:

Given:

Bacteria on day 1 = 5

On day 2, each bacteria got split into 5.

So, number of bacteria on day 2 = 5\times 5 = 25

Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.

So, number of of bacteria on day 3 = 25\times 5 =125

Therefore, the population of bacteria on day 3 is 125.

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3 years ago
What is the probability of getting eiather getting blue or green spinner that is 3/10 green and 1/3 blue
inysia [295]
The probability is 50% or half or 1/2
8 0
3 years ago
Please help me!!!!!!!!!!!
Rzqust [24]
2. 1 1/2 each
3. 1 1/4 each
4. 1 3/4 each
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5 0
3 years ago
Mrs. Bautista invested Php2700.00 part at 8% and the rest at 11% .How musch did she invest at each rate if her total annual inco
Margarita [4]

Answer:

The answer to the question is

She invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

Step-by-step explanation:

To solve the question we note that

Simple interest is given by \frac{P*R*T}{100} where

P= Principal, R = Rate and T = Time

If we call the first part P₁, T₁,  and R₁ and the second part

P₂, T₂,  and R₂

Then {P_1*(1+R_1*T_1}) +{P_*(1+R_2*T_2})  = 2460.00

= 2700×0.08×1 + P₂×0.11×1 = 2460  which gives

2244÷0.11 = P₂ or P₂ = Php 20,400.00

That is she invested

Php2700.00 at 8 % and

Php 20,400.00 at 11 %

5 0
3 years ago
Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul
Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 4

Sample mean, \bar{x} = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4\\H_A: \mu \neq 4

We use two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

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t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0
3 years ago
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