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Marta_Voda [28]
3 years ago
5

Will mark brainliest

Chemistry
2 answers:
Bas_tet [7]3 years ago
8 0

Answer: the first option

Explanation:

Direction has nothing to do with the speed/ kinetic energy

Sidana [21]3 years ago
5 0

Answer: A

Explanation:

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Which body fossil gives scientists information about how an animal moved?
Mazyrski [523]

Explanation:

The bone Wich is answer A

6 0
4 years ago
How does ground water become polluted
solniwko [45]

Ground Water can become polluted from when fossils and things make their way to the bottom of the ground and polluted the ground water

3 0
3 years ago
Read 2 more answers
. For the reaction 2HNO3 + Mg(OH), → Mg(NO3)2 + 2H20, how many grams of magnesium nitrate are produced from 8.00 mol of nitric a
GREYUIT [131]

Mass of Magnesium nitrate produced : 593.2 g

<h3>Further explanation</h3>

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + 2H₂0

mol HNO₃ = 8

From the equation, mol ratio of HNO₃ : Mg(NO₃)₂ = 2 : 1, so mol Mg(NO₃)₂ :

\tt \dfrac{1}{2}\times 8=4~moles

Mass Mg(NO₃)₂(MW=148,3 g/mol) :

\tt mass=mol\times MW\\\\mass=4\times 148,3 g/mol\\\\mass=593.2~g

6 0
3 years ago
How many atoms are in 3.5 moles of arsenic atoms?
solmaris [256]

Answer:

2.107×10²⁴

Explanation:

no of moles=no of particles/Avogadro's number

3.5=X/6.02×10²³

by cross multiplication

3.5×6.02×10²³

=2.107 ×10²⁴

5 0
3 years ago
Read 2 more answers
Determine the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
larisa [96]

333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.

Explanation:

Data given:

mass of iron 5 Kg or 5000

initial temperature = 50 degree centigrade

final temperature = 200 degrees centigrade

change in temperature (Δ T= 200 -50 degrees centigrade)

                                         = 150 °C

cp  (specific heat capacity of iron) = 0.444j/gram C

q (heat supplied) = ?

applying the formula,

q=mcΔT

putting the values in the equation:

q = 5000 X 0.444 X150

 q  = 333,000 Joules of energy.

The heat required 333,000 Joules of energy is required.

4 0
4 years ago
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