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vodomira [7]
4 years ago
8

The windchill index tells you

Physics
1 answer:
marshall27 [118]4 years ago
7 0
<span>The windchill index tells you A. how wind and temperature affect your body in winter. This is how you perceive the temperature outside due to the flow of air. The windchill index is always lower than the measured temperature outside. This is because wind increases the rate at which your body loses heat. For example, if it is 25 degrees outside, but there is a strong wind, the perceived temperature on your skin may be closer to 15 degrees.</span>
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A briefcase sits stationary in an elevator. The mass of the briefcase if 4.5 kg. The elevator then begins accelerating upwards a
Korvikt [17]

Answer:

D. 48.985 N

Explanation:

Newton's second law states that:

\sum F = ma

which means that the net force acting on an object is equal to the product between the object's mass and its acceleration.

The equation of the forces for the briefcase in the elevator therefore is given by:

N-mg=ma

where

N is the normal reaction exerted on the briefcase

(mg) is the weight of the briefcase, with

m = 4.5 kg being its mass

g = 9.8 m/s^2 is the acceleration of gravity

a = 1.10 m/s^2 is the acceleration

Here we chose upward as positive direction.

Solving for N, we find the normal force:

N=mg+ma=m(g+a)=(4.5)(9.81+1.10)=49.095 N

So the closest answer is

D. 48.985 N

3 0
3 years ago
I WILLL GIVE BRAINLYEST!!!
4vir4ik [10]

Answer:

Increasing temperatures evaporate water faster, causing an increase in salinity.

Explanation:

When the water molecules of the ocean become heated, they expand. ... Since warmer water thus can hold more salt and other molecules than cold water; it can have a higher salinity.

3 0
3 years ago
1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?
aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

<u>v = 30 m/s</u>

<u></u>

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

<u>v = 5 m/s</u>

<u></u>

3.

v = 20 m/s

λ = 0.5 m

f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}

<u>f = 40 Hz</u>

<u></u>

4.

v = 80 m/s

λ = 0.2 m

f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}

<u>f = 400 Hz</u>

<u></u>

5.

v = 120 m/s

λ = 0.4 m

f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}

<u>f = 300 Hz</u>

<u></u>

6.

v = 340 m/s

f = 440 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\

<u>λ = 0.772 m</u>

<u></u>

7.

v = 340 m/s

f = 880 Hz

\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\

<u>λ = 0.386 m</u>

<u></u>

<u></u>

8.

v = 250 m/s

f = 400 Hz

\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\

<u>λ = 0.625 m</u>

<u></u>

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

<u>v = 100 m/s</u>

<u></u>

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

<u>v = 50 m/s</u>

6 0
3 years ago
Mework
S_A_V [24]

The force applied by the student is 75 N

Explanation:

We can solve this problem by using Newton's second law, which states that the  force applied on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the force applied

m is the mass of the object

a is the acceleration

In this problem,

m = 50 kg

a=1.5 m/s^2

Substituting, we find the force applied by the student:

F=(50)(1.5)=75 N

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
An electron of mass 9.11 x 10^-31 kg has an initial speed of 4.00 x 10^5 m/s. It travels in a straight line, and its speed incre
yarga [219]

Answer:

a.     F = 2.32*10^-18 N

b.     The force F is 2.59*10^11 times the weight of the electron

Explanation:

a. In order to calculate the magnitude of the force exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

v^2=v_o^2+2ax         (1)

v: final speed of the electron = 6.60*10^5 m/s

vo: initial speed of the electron = 4.00*10^5 m/s

a: acceleration of the electron = ?

x: distance traveled by the electron = 5.40cm = 0.054m

you solve the equation (2) for a and replace the values of the parameters:

a=\frac{v^2-v_o^2}{2x}=\frac{(6.60*10^5m/s)^2-(4.00*10^5m/s)^2}{2(0.054m)}\\\\a=2.55*10^{12}\frac{m}{s^2}

Next, you use the second Newton law to calculate the force:

F=ma

m: mass of the electron = 9.11*10^-31kg

F=(9.11*10^{-31}kg)(2.55*10^{12}m/s^2)=2.32*10^{-18}N

The magnitude of the force exerted on the electron is 2.32*10^-18 N

b. The weight of the electron is given by:

F_g=mg=(9.11*10^{-31}kg)(9.8m/s^2)=8.92*10^{-30}N

The quotient between the weight of the electron and the force F is:

\frac{F}{F_g}=\frac{2.32*10^{-18}N}{8.92*10^{-30}N}=2.59*10^{11}

The force F is 2.59*10^11 times the weight of the electron

8 0
3 years ago
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