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Setler79 [48]
3 years ago
13

Solve the system of equations

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

Option c is right:

(-6 , 2)

Step-by-step explanation:

( -6 , 2)

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Write a polynomial in factored form that has the given zeros:
wlad13 [49]

Answer:

f(x) = (x + 4)^2*(x - 5)^3

Step-by-step explanation:

For a polynomial P(x) with zeros (or roots):

x₁, x₂, ..., xₙ

And a leading coefficient (the one that multiplies the term of highest degree) A, we can write the polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

Now, some of these roots can be repeated.

For example if x₁ = x₂

Then we say that the root x₁ has a multiplicity of two.

And we write the polynomial as:

P(x) = A*(x - x₁)^2*(x - x₃)*....*(x - xₙ)

Now, if we have a polynomial with the roots (or zeros):

Zero at -4 with a multiplicity of 2 (we have the root x = -4 two times)

Zero at 5 with a multiplicity of 3 (we have the root x = 5  3 times)

(And a leading coefficient A =  1, I assume)

This polynomial will be written as:

f(x) = (x - (-4))*(x - (-4))*(x - 5)*(x - 5)*(x - 5)

f(x) = (x + 4)*(x + 4)*(x - 5)*(x - 5)*(x - 5)

f(x) = (x + 4)^2*(x - 5)^3

The correct option is the third one:

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3 years ago
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Answer:

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Step-by-step explanation:

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