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Anna007 [38]
3 years ago
11

Please solve 6+4/5b=9/10b

Mathematics
1 answer:
Verizon [17]3 years ago
5 0
6+8/10b=9/10b
6=1/10b
60=b
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After 3 hours of of driving, Paul had gone 183 miles. What was his average rate of speed? Explain your answer.
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s(av) =  \frac{∆x}{∆t}  \\

s(av) = average \:  \: speed

∆x = covered \:  \: distance

∆t = time \:  \: of \:  \: the \:  \: covered \:  \: distance \\

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s(av) =  \frac{183}{3}  \\

s(av) = 61 \:  \:  \frac{mile}{hour}

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3 years ago
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One day there could be 80 phone calls and the next there could be 2. It is continuously random.

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3 years ago
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Is y=22x-65 a linear equation
sveta [45]
y=22x-65
yes is a linear line because linear mean a straight line

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3 years ago
Solve for m: am/c = n
chubhunter [2.5K]

Hey there! I'm happy to help!

We want to get m all by itself on one side of the equation. To do this, we use inverse operations on both sides of the equation to cancel out variables on one side to isolate m.

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3 years ago
Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th
RSB [31]

Answer:

The volume of the solid is:

\displaystyle\frac{19\pi}{6}

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1

Since the region is the one for x\ge 0 then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so 8x-9-x^2 (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the 2\pi and distributing the x:

=\displaystyle2\pi \int_0^19x-8x^2-x^3dx

Then use the basic rule to integrate:

=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1

Then evaluate the antiderivative in the limits and subtract:

=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}

So the volume of the solid is \displaystyle\frac{19\pi}{6}

4 0
3 years ago
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