3. I believe the answer is C & A, arrange the boards so that the diagonals bisects and are perpendicular. A rhombus is a Quadrilateral with all its sides equal to each other. The diagonals of a rhombus are perpendicular to each other and bisects each other.
4.The corresponding pairs of base angles of a trapezoid add up to 180 degrees, (they are supplementary), While all the angles (the four angles add up to 360 degrees)
Therefore; in this case the two angles are equal
hence, 19x + 8 = 11x+16 solving for x
x = 1
substituting x in either of the expression
The angle = 27 °
5. The diagonals of a rhombus bisects each other at right angles; the are perpendicular,
hence,
m∠1= 10x = 90
x = 9
m∠2 = x + y =90
but x = 9,
thus, y = 81
m∠3 = 5z= 90
z =18
10. A kite is a Quadrilateral with two equal sides and the other two sides equal.
thus, y-4 = 5x+2 and x +22 = 3x +10
solving for x
x+22 = 3x +10
2x = 12
x = 6
y-4 = 5x +2
y-4 = 5(6) +2
y = 36.
11.a. RHOM is a Quadrilateral with four equal sides
b. The four sides RH, OH, OM, and RM are equal, They are all congruent
c HM and HM is the diagonal, which forms the corresponding sides of triangle MRH and triangle MOH
d. Triangle MRH and triangle MOH are congruent, SSS, and similar to each other.
First, you set up your equation then you put the pieces together to get the answer
Answer:
y = 5 and x = -3
Step-by-step explanation:
Given,
y = x + 8 ...............( equation 1 )
x + y = 2 ...............( equation 2 )
Now, by substituting the value of y in equation 2, we get;
⇒ x + x + 8 = 2
⇒ x = -3
and now, by substituting the value of x in equation 1, we get;
⇒ y = -3 + 8
⇒ y = 5
