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azamat
3 years ago
9

HELP ASAP

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer:

its A or the first one ;)

Step-by-step explanation:

zavuch27 [327]3 years ago
6 0
2rd one I could be wrong tho
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A cheetah runs 296 feet in 4 seconds. How far could a cheetah run in 10<br> seconds at this rate?
melomori [17]

Answer:

740 feet

Step-by-step explanation:

The speed of the cheetah is 74 feet per second:

speed = distance ÷ time

= 296 ÷ 4 = 74 feet per second

In 10 seconds:

distance = speed × time

= 74 × 10

= 740 feet

4 0
3 years ago
Read 2 more answers
Plsss help meeee I need the answer!!
kipiarov [429]

Answer:

A. <em>p=3-2h</em>

<em>h</em><em>=</em><em>9-p</em>

Step-by-step explanation:

Justin buys 3 less than twice as many <em>h</em>ot dogs

5 0
3 years ago
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
Evaluate.4 2 – 6+2 +3 =
Charra [1.4K]
4^2-6\text{ / 2 + 3 = ?}4^2\text{ - }\frac{6}{2}\text{ + 3 = ? }\Rightarrow\text{ 16 - 3 + 3 = ?}

16 - 3 + 3 = 16

3 0
1 year ago
(-2,3) and slope m =9
AlladinOne [14]
So what is this about???

8 0
3 years ago
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