1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zheka24 [161]
3 years ago
8

Give the oxidation state of the metal species in each complex. ru(cn)(co)4 -

Chemistry
2 answers:
Ann [662]3 years ago
6 0

The oxidation state of the Ru metal in the complex {\left[{{\text{Ru}}\left({{\text{CN}}}\right){{\left({{\text{CO}}}\right)}_4}}\right]^-} is \boxed{{\text{zero}}} .

Further explanation:

Oxidation number:

The oxidation number is used to represent the formal charge on an atom. It also shows that gain or loss of electrons by the atom. Oxidation number can be a positive or negative number but cannot be fractional.

The rules to identify the oxidation state:

(1) The oxidation state of an atom in the elemental form is zero.

(2) The total charge on the species is equal to the sum of the oxidation state of individual atoms.

(3) The oxidation state of halides is -1. For example, fluorine, chlorine, bromine, iodine have -1 oxidation state.

(4)Hydrogen has a +1 oxidation state.

(5) Oxygen has an oxidation state -2.

(6) In a coordination compound, neutral ligands have zero oxidation state and negative ligands such as CN have -1 oxidation.

The given compound is {\left[{{\text{Ru}}\left({{\text{CN}}}\right){{\left({{\text{CO}}}\right)}_4}}\right]^-}

Here, CN is a negative ligand thus oxidation state is -1 and CO is a neutral ligand thus it has 0 oxidation state. Also, the complex has -1 negative charge.

The expression to calculate the oxidation state in {\left[{{\text{Ru}}\left({{\text{CN}}}\right){{\left({{\text{CO}}}\right)}_4}}\right]^-} is,

\left[{\left({{\text{oxidation state of Ru}}}\right)+\left({{\text{oxidation state of CN}}}\right)+4\left({{\text{oxidation state of CO}}}\right)}\right]=-1

…… (1)

Rearrange equation (1) for the oxidation state of Ru.

{\text{Oxidation state of Ru}}=\left[{-\left({{\text{oxidation state of CN}}}\right)-4\left({{\text{oxidation state of CO}}}\right)-1}\right]

…… (2)  

Substitute -1for the oxidation {\text{state}}  of CN and 0 for the oxidation state of CO in equation (2).

\begin{aligned}{\text{Oxidation state of Ru}}&=\left[{-\left({-{\text{1}}}\right)-4\left({\text{0}}\right)-1}\right]\\&=0\\\end{aligned}

The oxidation state of Ru is zero.

Learn more:

1. General statement that is not applied on metals: <u>brainly.com/question/2474874 </u>

2. The neutral element represented by the excited state electronic configuration: <u>brainly.com/question/9616334 </u>

Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Coordination complex

Keywords: Oxidation state, metal complex, ru(cn)(co)4-, formal charge, cynide, carbonyl, zero, hydrogen, oxygen, 0 and -1.

kogti [31]3 years ago
3 0
The given complex ion is as follow,

                                              [Ru (CN) (CO)₄]⁻

Where;
            [ ]  =  Coordination Sphere

            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
            -1  =  overall charge on sphere

             0  =  Charge on neutral CO

            -1  =  Charge on CN

So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

                               Ru - 1 + 0  =  -1

                               Ru - 1  =  -1

                               Ru  =  -1 + 1

                               Ru  =  0
Result:
          <span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
You might be interested in
When you are balancing chemical reactions ('equations'), what must you never touch?
timofeeve [1]

You should never touch the subscripts, as that will change the composition. Hope I helped!

8 0
3 years ago
Read 2 more answers
An aqueous solution has a mass of 490 grams containing 8.5 × 10-3 gram of calcium ions. The concentration of calcium ions in thi
Arada [10]
The concentration may be expressed as % m/m, this is the mass of ions in 100 mass units of solution, whose formula is:

% m/m = [mass of ions / mass of solution]*100

Then,

%m/m = [8.5*10^ -3 grams of calcium ions] / [490 grams of solution] * 100 =

% m/m = 1.74 * 10^ -5 %

Answer: 1.74 * 10 ^ -5 % 
5 0
3 years ago
PLEASE HELP ME I DONT WANT TO FAIL
Grace [21]

Answer: Within each element square, information on the element's symbol, atomic number, atomic mass, electronegativity, electron configuration, and valence numbers can be found. At the bottom of the periodic table is a two row block of elements that contain the lanthanoids and actinides.

4 0
3 years ago
How many sig figs in each?<br> -27.43<br> -1.90<br> -101
GarryVolchara [31]
1. Has 4 sig figs, all non zeros are significant
2. 3 sig figs trailing zero after a decimal
3. 3 sig figs
5 0
2 years ago
If calcium has two valence electrons and fluorine has seven, how many fluorine atoms are needed to form an ionic bond with calci
MaRussiya [10]
Fluorine needs one electron to fill its orbital shell. It needs 8 valence electrons
5 0
3 years ago
Read 2 more answers
Other questions:
  • Write the balanced equation for each of the following changes and identify whether heat is a product or needed to start the reac
    14·1 answer
  • 1 3.1.2
    11·1 answer
  • What replaced the early pharmacists role in the production of medicine
    6·1 answer
  • A number of substances and their chemical formulas are listed below. Check the ones that are compounds. neon (Ne) carbon monoxid
    8·1 answer
  • If an aqueous solution of lead(II) nitrate (Pb(NO3)2) is mixed with an aqueous solution of potassium chloride (KCl) the precipit
    6·1 answer
  • Classify each of the following molecules as purely covalent, non-polar covalent, polar covalent,
    15·1 answer
  • Explain the term respiration and how this process increases the percentage of carbon dioxide in the atmosphere.
    9·1 answer
  • What would the chemical formula be of a compound that has Hydrogen and Carbon in it?
    5·2 answers
  • How much water must be added to 15 ml of a 2.5 M solution of sodium chloride to make a 2.0 M solution of sodium chloride?
    9·1 answer
  • A light year is a measure of<br> O length<br> O speed<br> O time<br> O volume
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!