Question

Log√30 - log√6 + log√2

Answer 1

Assuming, it's decimal logarithm.

$\log\sqrt{30}-\log\sqrt6+\log\sqrt2=\log\dfrac{\sqrt{30}\cdot\sqrt2}{\sqrt6}=\log \sqrt{10}=\dfrac{1}{2}\log 10=\dfrac{1}{2}\cdot 1=\dfrac{1}{2}$