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scoray [572]
3 years ago
8

Log√30 - log√6 + log√2

Mathematics
1 answer:
Arada [10]3 years ago
3 0

Assuming, it's decimal logarithm.

<h3>\log\sqrt{30}-\log\sqrt6+\log\sqrt2=\log\dfrac{\sqrt{30}\cdot\sqrt2}{\sqrt6}=\log \sqrt{10}=\dfrac{1}{2}\log 10=\dfrac{1}{2}\cdot 1=\dfrac{1}{2}</h3>
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So, Vladimir is correct.

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