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siniylev [52]
3 years ago
11

PLEASE HELP TIMED TEST What is the value of x in the matrix equation below?

Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

x = 1

Step-by-step explanation:

Given the matrix;

-2\left[\begin{array}{ccc}x&-1\\3&5\end{array}\right] + \left[\begin{array}{ccc}3&8\\-1&6\end{array}\right] = \left[\begin{array}{ccc}x&10\\-7&-4\end{array}\right]

Converting to equations

From the first row of each matrices

-2x + 3 = x

Collect the like terms

-2x - x = -3

-3x = -3

x = -3/-3

x = 1

Hence the value of x is 1

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Answer:

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Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

8x+6y = -54

Subtract 8x from each side

8x+6y-8x = -8x-54

6y = -8x-54

Divide each side by 6

6y/6 = -8x/6 -54/6

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5 0
3 years ago
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Find the value of s if 57+s=68
olga2289 [7]

Answer

s = 11

Step-by-step explanation:

Find the value of S:

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Which of the following inverse functions are defined for x=-1/2? Select all that apply.
Aleksandr-060686 [28]

Answer:

A, B, E, and F  

Step-by-step explanation:

sinx and cosx are defined for all values of x. So, sin⁻¹x and cos⁻¹x  are also defined for all values of x.  

A and E are correct.

tanx is defined for all values of x.

However, tan(nπ) = 0 at when n is an integer. So, tan⁻¹(±nx) is undefined. However, tan⁻¹(-½x) is defined, because -½ is not an integer.

B and F are correct.

C and D are <em>wrong</em>. Both sec⁻¹x  and csc⁻¹x are undefined when -1 < x < 1, and -½ is in this forbidden region.

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3 years ago
A wheel has a radius of 15 cm. Approximately how far does it travel in 4 revolutions?
ArbitrLikvidat [17]
Radius is 15 cm
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7 0
3 years ago
If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
3 years ago
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