Which expression shows the prime factorization of 66? please i need help so bad its a test

The box-and-whisker plot below represents some data set. What percentage of the

myrzilka [38]

Answer:

25 percent; each section of the box plot counts as 25%

4 0

2 years ago

WILL MARK BRAINLIEST Suppose MyBook sent out 950 surveys. Which of these numbers of surveys being returned would prevent nonresp

Oliga [24]

Answer:

C) 9

Step-by-step explanation:

The response is very low

7 0

4 years ago

Read 2 more answers

Consider the function FX equals -2/3 X -24 which conclusions can be drawn about F negative 1X select two options a F negative 1X

omeli [17]

The conclusions that can be drawn about f–1(x) are:

$f^-^1(x)$ has an x-intercept of (-36, 0)
$f^-^1(x)$ has a range of all real numbers.

<h3>Calculations and Parameters:</h3>

Given:

$f(x) = \frac{-2}{3}x - 24$

$f(x) + 24 = \frac{-2}{3}x$

To find x, we would multiply both sides by -2/3

= $x= \frac{-3}{2} (f(x) + 24)$

$f^-^1(x) = -\frac{3}{2} (0) - 36$

$f^-^1(x) = -36$

Therefore, $f^-^1(x)$ has an x-intercept of (-36, 0)

Furthermore, $f^-^1(x)$ has a range of all real numbers.

Read more about real numbers here:

brainly.com/question/17020343

#SPJ1

5 0

2 years ago

Whats the answer to 1/2(5×-8)=-9

REY [17]

Answer:

I do not know if that x is a multiply sign or a variable so I'm going to answer both

If the x is a multiplication sign then the answer is -20 = -9

If the x is a variable then the answer is x = -2

Step-by-step explanation:

1/2(5 * -8) = -9

(1 * 5 * -8)/2 = -9

(5 * -8)/2 = -9

-40/2 = -9

-20 = -9

-20 ≠ -9

1/2(5x - 8) = -9

1(5x -8)/2 = -9

(5x - 8)/2 = -9

2((5x - 8)/2) = -9 * 2

2(5x - 8)/2 = -9 * 2

5x - 8 = -9 * 2

5x - 8 = -18

+8 +8

------------------

5x = -10

x = -10/5

x = -2

5 0

3 years ago

Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p

zubka84 [21]

Answer: The required answers are

(a) 0.25, (b) 0.62, (c) 6.

Step-by-step explanation: Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

$P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.$

(a) The probability of getting 5 heads is given by

$P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.$

(b) The probability of getting 5 or more than 5 heads is

$P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.$

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

$P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.$

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0

4 years ago