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valentinak56 [21]
3 years ago
11

The ratio of zinc to copper in some alloy is 2 to 5. If 60 kilograms of zinc are used, how many kilograms of copper are needed t

o make this alloy
Chemistry
1 answer:
NemiM [27]3 years ago
5 0

Answer:

The correct answer is 150 kilograms.

Explanation:

Based on the given information, the ratio of zinc and copper within the alloy is 2:5. The amount of zinc used in the alloy is 60 kg. Now the amount of copper used within the alloy would be,

Zinc/Copper = 2/5

60/Copper = 2/5

Copper(Cu) = 60*5/2

Cu = 150 Kilograms.

Thus, the amount of Cu used in the alloy is 150 Kg.

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What is the molar mass of a compound if 25.0 g of the compound dissolved in 750. Ml gives a molarity of 0.290 m?
wlad13 [49]

Answer:

115g/mol

Explanation:

To get the molar mass, we know that the it is equal to the mass divided by the number of moles. We have the mass but we do not have the number of moles.

We get this by working through the solution information. Firstly, we need to know the number of moles in 750ml for a molarity of 0.29m

Now, since 0.29 moles is present in 1000ml, x moles will be present in 750ml

The value of x is obtained as follows:

x = (750 * 0.29)/1000 = 0.2175 moles

Now since we have the number of moles, we can then obtain the molar mass.

Molar mass = mass/number of moles = 25.0g/0.2175 = 114.94 approximately 105g/mol

6 0
3 years ago
Which is the best definition of an ecosystem?
vredina [299]

Answer:

last one is the correct and most suitable option.

Hope it helps!!!

6 0
3 years ago
Read 2 more answers
in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat
Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

a)

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

c)

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0
3 years ago
½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole 21.0 kcal/mole + C(s) + 2S(s) → CS2(l) What type of reaction is represented by the
wlad13 [49]

<u>Answer:</u>

Exothermic Reaction are those reaction, in which energy is released while in endothermic reaction are those, in which energy is absorbed.

<u>Explanation:</u>

First Reaction:

As in this reaction, energy is released

½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole

so it is <em>exothermic reaction</em>

Second reaction:

As in this reaction, energy is absorbed

21.0 kcal/mole + C(s) + 2S(s) → CS2(l)

so it is <em>endothermic reactions</em>.


7 0
4 years ago
Read 2 more answers
A balloon at 25°C has 30 L. What will the balloon's volume at 35°C?
anygoal [31]

The balloon's volume at 35°C : V₂=31.01 L

<h3>Further explanation</h3>

Given

T₁ = 25°C+273 = 298 K

V₁ = 30 L

T₂ = 35 °C + 273 = 308 K

Required

The new volume (V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(30 x 308)/298

V₂=31.01 L

8 0
3 years ago
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