Answer:
Explanation:
Alkaline earth metals are in group 2. The number of valence electrons of elements in group 2 is 2.
Answer:
1.004×10²²
Explanation:
The molar mass of carbon is 12 g/mol
which means that:
<u>1 mole of carbon atoms has a mass of 12 grams.</u>
Since, diamond is a allotrope of carbon.
Mass of 1.00-carat diamond in grams is:
1.00 carat = 0.200 g
<u>
Since, 1 mole of C contains 6.022×10²³ atoms of C</u>
So,
12 grams contains 6.022×10²³ atoms of C
1 gram contains 6.022×10²³/ 12 atoms of C
0.200 gram contains (6.022×10²³/ 12)×0.200 atoms of C
Thus,
<u>1 carat diamond contains 1.004×10²² atoms of C.</u>
Answer:
Explanation:
The result will be affected.
The mass of KHP weighed out was used to calculate the moles of KHP weighed out (moles = mass/molar mass).
Not all the sample is actually KHP if the KHP is a little moist, so when mass was used to determine the moles of KHP, a higher number of moles than what is actually present would be obtained (because some of that mass was not KHP but it was assumed to be so. Therefore, there is actually a less present number of moles than the certain number that was thought of.
During the titration, NaOH reacts in a 1:1 ratio with KHP. So it was determined that there was the same number of moles of NaOH was the volume used as there were KHP in the mass that was weighed out. Since there was an overestimation in the moles of KHP, then there also would be an overestimation in the number of moles of NaOH.
Thus, NaOH will appear at a higher concentration than it actually is.
well, yes it will continue to swing but not forever. it will just a long time but eventually stop. the reason is because of the air resistance which will continue to damp the motion until the bob stops
Answer:
531–1532 – Pizarro's third voyage to Peru. Spaniards form a bond with the Natives (Huancas, Chankas, Cañaris and Chachapoyas) who were under the oppression of the Inca Empire, and Pizarro includes them among his troops to face the Incas. Atahualpa is captured by Spanish.
Explanation: Is this right ?
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