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Alborosie
3 years ago
13

Janice is given a mixture of alcohol and water. The teacher tells her that she can use temperature to separate these compounds.

What property is being demonstrated by this experiment.
A) conduction
B) density
C) solubility
D) boiling
Chemistry
2 answers:
Korolek [52]3 years ago
6 0
Since Janice was given a mixture of alcohol and water, her teacher suggested that she use temperature to separate the two substances. The property demonstrated by the experiment is D. boiling. The boiling point refers to the temperature at which the liquid phase of the substance will turn into vapor. Water is known to boil at 100°C at atmospheric pressure while alcohols are generally known to have a boiling point lower than that of water. In this experiment, knowing that the two substances had a significant difference in boiling temperature was crucial to be able to separate them into their pure substances.
4vir4ik [10]3 years ago
5 0

Answer: D) boiling

Explanation:

In order to separate a mixture of alcohol and water the mixture can be heated until the alcohol boils. The boiling point of alcohol is lower than water. The alcohol will boil off leaving the water.

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3 years ago
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

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