1) 
We can solve this part by using Newton's second law:
(1)
where
F is the net force
m is the mass
a is the acceleration
There are two forces acting on the boat:
forward
backward
So the net force is
We know that the mass of the boat is
m = 1177.5 kg
So we can now use eq.(1) to find the acceleration:
2) 161.0 m
We can solve this part by using the following suvat equation:
where
s is the distance travelled
u is the initial velocity
t is the time
a is the acceleration
Here we have
u = 0 (the boat starts from rest)
Substituting t = 17.7 s, we find the distance covered:
3) 18.2 m/s
The speed of the boat can be found with the following suvat equation
where
v is the final velocity
u is the initial velocity
t is the time
a is the acceleration
In this case we have
u = 0 (the boat starts from rest)
And substituting t = 17.7 s, we find the final velocity:
And the speed is just the magnitude of the velocity, so 18.2 m/s.
Answer:
(a) Position Vectors V₁= -2î km, V₂=5î km
(b) Displacement Δx=7 km
Explanation:
Given data
Distance=2 km west at t=0
Distance=5 km east at t=6 min
Positive x is the east direction
To find
(a)Car position vector at given times
(b)Displacement between 0 to 6.0 min
Solution
For Part (a) car position vector at given times
At t=0 the distance=2 km west so conclude that x₁=-2 because it is in negative side So vector V₁
V₁= -2î km
At t=6.0 the distance=5 km east so conclude that x₂=5 because it is in positive side So vector V₂
V₂=5î km
For (b) displacement between 0 to 6.0 min
According to following mathematical law we can conclude that
Δx=x₂-x₁
Δx=5-(-2)km
Δx=7 km
1b) the atom could lose its valence electron
c) protons are equal to electrons so there is no need to include it
d) the atom would need to gain electrons to fill its valence shell to become negative
Your answer is B i know this because i took this last week
Answer:
maybe it's because a bucket of water has more density than egg B
